The higher the _____ in the infrared (IR) spectra, the greater the energy required to vibrate the bond. a) absorbance b) transmittance c) emission d) wavenumber e) wavelength
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Please don't provide handwriting solution
The higher the _____ in the infrared (IR) spectra, the greater the energy required to vibrate the bond.
a) absorbance
b) transmittance
c) emission
d) wavenumber
e) wavelength
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- Can IR spectroscopy be used for quantitative analysis? >No, because IR spectroscopy only records vibrational frequency of bonds. >No, because IR spectroscopy only identifies the types of covalent bonds. >Yes, because the transmittance of the analyte is proportional to concentration. >Yes, because the absorbance of the analyte is proportional to concentration.According to Beer-Lambert's Law, which of the following does the absorbance NOT depend on? A.) Color of the solution.B.) Distance that light has traveled through the sampleC.)Solution concentrationD.)Molar extinction coefficient ofsample.2. According to the Beer-Lambert law absorbance is proportional to concentration at each wavelength. In principle, one could choose any wavelength for quantitative estimations of concentration. However, we generally select the wavelength of maximum absorbance for a given sample and use it in our absorbance measurements. Especially, one should avoid the steep portions of the spectrum. Why? 3. Which concentration range a dilute or a concentrated one - is chosen for accurate determinations of unknown concentrations?
- Most alkenes absorb at a shorter wavelength than alkadienes. Explain.The properties of a molecule that are most frequently calculated are geometry, energy (compared to that of other isomers), and spectra. Why is it more of a challenge to calculate “simple” properties like melting point and density? Hint: is there a difference between a molecule X and the substance X?Examine the geometry of the molecule in the 3D window. Use the geometry to determine the bond types. carbon-carbon approximate bond type length single - 0.15 nm double - 0.13 nm aromatic - 0.14 nm • Double-click on an atom, and then move cursor over another one to get a distance (click off of the molecule to end) • Double-click on an atom, click on a second and move cursor over a third to get the angle about the second atom (click off of the molecule to end) JSmol Are there one or more rings in the molecule that are completely planar? Do the C-C distances in all of the rings fall between 0.135 and 0.145 nm? Are the rings in the compound aromatic, non-aromatic or mixed?