The following information was recorded by a student team working to prepare nickel sulfate. Plan: Prepare NiSO4 by reacting NiO with 6 M H2SO4 The expected product is NiSO4·6H2O. We will filter the crystals from the reaction solution to get the product.  NiO +  H2SO4 -->  NiSO4 +  H2O molar mass of NiO: 74.69 g/mol molar mass of NiSO4: 154.75 g/mol molar mass of NiSO4·6H2O: 262.85 g/mol mass of NiO used: 7.5 g volume of 6M H2SO4 used: 50 mL heated the solution for 30 minutes, cool and filtered the crystals mass of product: 17.4 g Two students calculated percent yield using this data.  One student got 66.2% and another got 112%.  Based on this information, which of the following statements are true.  One or more statements are correct.   Group of answer choices The percent yield of 112% was calculated using the molar mass for the hydrated product. The percent yield of 66.2% was calculated using the molar mass for the anhydrous product. Both percent yields are incorrect because the student used the wrong number of moles. The percent yield of 112% was calculated using the molar mass for the anhydrous product. The percent yield of 66.2% was calculated using the molar mass for the hydrated product.

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The following information was recorded by a student team working to prepare nickel sulfate.

Plan: Prepare NiSO4 by reacting NiO with 6 M H2SO4 The expected product is NiSO4·6H2O. We will filter the crystals from the reaction solution to get the product. 

NiO +  H2SO4 -->  NiSO4 +  H2O

molar mass of NiO: 74.69 g/mol
molar mass of NiSO4: 154.75 g/mol
molar mass of NiSO4·6H2O: 262.85 g/mol

mass of NiO used: 7.5 g
volume of 6M H2SO4 used: 50 mL

heated the solution for 30 minutes, cool and filtered the crystals

mass of product: 17.4 g

Two students calculated percent yield using this data.  One student got 66.2% and another got 112%. 

Based on this information, which of the following statements are true.  One or more statements are correct.  

Group of answer choices
The percent yield of 112% was calculated using the molar mass for the hydrated product.
The percent yield of 66.2% was calculated using the molar mass for the anhydrous product.
Both percent yields are incorrect because the student used the wrong number of moles.
The percent yield of 112% was calculated using the molar mass for the anhydrous product.
The percent yield of 66.2% was calculated using the molar mass for the hydrated product. 
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