The block shear strength of the tension member as shown in figure is (round off to two decimal places). Assume grade of plate Fe410. 45 mm 35 mm O 50 mm 100 mm ISA 80 x 50 x 8 mm (M20 bolt of grade 4.6 is used) KN
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- 4. An UPE 300 is to be used as a tension member and it is bolted to a 10mm thick gusset plate with bearing type 8-M20 8.8 bolts as shown in the figure below. a. Check all spacing and edge distance requirements. b. Compute the allowable tensile strength of the channel UPE 300. Don't consider shear strength of the bolts and bearing strength of the bolt holes. [all dimensions are in mm] Material both for gusset plate and UPE 300: S275 F-275N/mm² Fu=430N/mm² UPE 300 Ag = 5660 mm² tw 9.5 mm x = 28.9 mm 70 160 70 + 10mm thick gusset plate +50+ 80 -80-80-50 o +50+80 -80 80-50 UPE 300The block shear strength of the tension member as shown in figure is (round off to two decimal places). Assume grade of plate Fe410. 45 mm 35 mm 50 mm 100 mm ISA 80 x 50 x 8 mm (M20 bolt of grade 4.6 is used) KNProblem (4): A36 steel is used for the tension member shown in Figure below. a. Determine the nominal strength based on the gross area. b. Determine the nominal strength based on the net area. PL 300mmx17mm 150 75 75 75 75 75 125 ImmmmTmm"" mmn mm mm 50mm 100mm 100mm 50mm 19mm diameter bolts Problem (5): The tension m shown in Figur
- Prepare an excel file and to find a) area of the bolt, b) Average Shear Stress Bolt c) Bearing Area Stress and d) allowable stress. Applied force range – 500 to 1000 N (in step of 100 N) Bolt diameter range – 10 to 25 mm (in step of 5 mm) Plate thickness – 10 mm Consider ultimate tensile strength as 460 N/mm2. And consider factor of safety as 1.5.For the two lines of M20 bolts shown in the figure, determine the design tensile strength (kN) of the plate if it is 12mm thick. Use the pitch (s) that gives it a net area DEFG equal to the one along ABC. D 50 3. 50 50 IG ic Pitch PitchDetermine block shear strength of tension member shown in figure if grade of steel is Fe-410 ISA 100 × 75x8 mm 50 100 55 35 O 20 mm dia bolt hole
- An A36 tension member shown in the figure is connected with three 19 mm diameter bolts. Dia. Of bolt hole = 22 mm. %3D 50, 100 100 99.45 50.55 100 Properties of 150 mm x 100 mm x 12.5 mm angle A - 3065 mm- y - 50.55 mm Fy - 248 MPa Fu 400 MPa Determine the design strength due to yielding in the gross section. (kN)Material Strengths: Fy = 248 MPa, F = 400 MPa For the two lines of bolt holes, the pitch is the value that will give a net area DEFG equal to the one along ABC. The diameter of the holes is 22 mm. The thickness of the plate is 12 mm. Determine the LRFD design tensile strength based on yielding on gross area. D A to 50 1 ÓB 50 50 ic O 410 kN O 464 kN O 446 kN O 401 KN F IG Pitch Pitch KISS|YThe connection shown is subjected to a tensile force of P = 100 kN. The allowable shear stress for the bolts is 100 MPa. Assume each bolt supports an equal portion of the load. Determine the required diameter of the bolts. a. 20.6 mm b. 25.2 mm c.35.7 mm d.17.8 mm choose letter of correct answer
- Use ASD to determine the width of the 5/8 inch thick A36 plate subjected to tension as shown below. The dead load effect is PD=85 kip while the live load effect is PL=80 kip. Two rows of 5/8 inch standard bolts will be used for the connection and the plate width can be manufactured in 1 inch increments. Assume that the larger connected plate does not fail. Consider the limit states of gross tensile yield and tensile rupture. Find the required tension strength, Pa, for the controlling ASD load combination. Determine the width necessary for the plate to resist gross tensile yield. Determine the width necessary for the plate to resist tensile rupture. Report the required plate width.The butt connection shows 8-22 mm diameter bolts spaced as shown below. P- 50 100 50 50 100 50 16 mm +HHHH 40 80 40 12 mm Steel strength and stresses are: Yield strength, Fy = 248 MPa Ultimate strength, Fu = 400 MPa Allowable tensile stress on the gross area = 148 MPa Allowable tensile stress on the net area = 200 MPa Allowable shear stress on the net area = 120 MPa Allowable bolt shear stress, Fv = 120 MPa Based on the gross area of the plate. Based on the net area of the plate. Based on block shear strength. Bolt hole diameter = 25 mm Calculate the allowable tensile load, P, under the following conditions:2. For the figure shown, calculate the net area of the 10 x 200 mm plate. The plate is connected at its end with two lines of 20 mm bolts. Using LRFD, determine the load P that the plates can carry against tensile yielding in the gross section and the tensile rupture in the net section. Use A-36 steel. PL 5x200mm PL 5x200mm Pu PL 10x200mm Pu