The AW method is to be used to select the better alternative of the two machines listed below, at 10% per year. Answer the below questions: Machine R Machine S First cost, $ 250,000 497,732 Annual operating cost, $ per year 40,000 50,000 Salvage value, $ Life, years 20,000 30,000 3 5. The AW of Machine S=

The AW method is to be used to select the better alternative of the two machines listed below, at 10% per year. Answer the below questions: Machine R Machine S First cost, $ 250,000 497,732 Annual operating cost, $ per year 40,000 50,000 Salvage value, $ Life, years 20,000 30,000 3 5. The AW of Machine S=

Essentials Of Investments

11th Edition

ISBN:9781260013924

Author:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.

Publisher:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.

Chapter1: Investments: Background And Issues

Section: Chapter Questions

Problem 1PS

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Compare the machines below using present worth analysis at i10% per year and find which one should be selected Machine Y First Cost Operating Cost Savage Lfe cycle Machine X 20.000 3.000 3.000 3years Firat Cost 30.000 .000 Annuel Operating Cost Salvage Life cycle 3.000 6 yoars
For the below ME alternatives, which machine should be selected based on the AW analysis. MARR=10% First cost, $ Annual cost, $/year Salvage value, $ Life, years Machine A 15000 B- AW for machine B= 8,342 4,000 Answer the below questions : Machine B 6 20,447 6,000 5,000 Machine C 10000 4,000 1,000
A manufacturing company is trying to decide between the two machines shown below. Determine which machine should be selected on the basis of rate of return. Assume the MARR is 20% per year. Machine A Machine B Initial Cost, $ -18,000 -35,000 Annual operating cost, $/year -4,000 -3,600 Salvage value, $ 1,000 2,700 Life, years 3 6
For the below ME alternatives, which machine should be selected based on the AW analysis. MARR-10% Machine B 27,724 6,000 Machine A Machine C First cost, $ 15000 10000 Annual cost, S/year Salvage value, $ Life, years 8,293 4,000 4,000 5,000 1,000 Answer the below questions: B- AW for machine B= For the below ME alternatives, which machine should be selected based on the AW analysis. MARR 10%. Machine A 15000 Machine B Machine C 12,409 30000 First cost, $ Annual cost, $/year Salvage value, $ Life, years 17,181 6,000 4,000 4,000 5.000 1,000 Answer the below questions: C- AW for machine C=
Use Service-Output Method. A Machine costs ₱80,000 and an estimated life of 10 years with a salvage value of ₱5,000. Assuming that the total service of the machine is 1,497,600 hours and the number of working days per year is 260 days. What is the book value after 4 years if the machine production time a is 24 hours? Answer: BV4 = P 78,750.00Show Solution
Your boss has told you to evaluate the cost of two machines.After some questioning, you are assured that they have thecosts shown at the right. Assume:a) The life of each machine is 3 years.b) The company thinks it knows how to make 14% oninvestments no riskier than this one.Determine via the present value method which machine topurchase. MACHINE A MACHINE BOriginal cost $13,000 $20,000Labor cost per year 2,000 3,000Floor space per year 500 600Energy (electricity) per year 1,000 900Maintenance per year 2,500 500Total annual cost $ 6,000 $ 5,000Salvage value $ 2,000 $ 7,000
Machines that have the following costs are under consideration for a robotized welding process. Using an interest rate of 10% per year, determine which alternative should be selected on the basis of a present worth analysis? Machine X Machine Y First cost, $ -200,000 -400,000 Annual operating cost, $ per year -40.000 -50,000 Salvage value, $ 80,000 90,000 Life, years 3 Solution: PW Machine x =5 (Use the right sign) PW Machine Y = 5 (Use the right sign) So, the best alternative is Machine
a- At 10%, find PW for the following Table Warehouse cost equipment cost Installation cost Annual maintenance costs Annual Revenues Salvage Machine life 0 1 2 3 -90,000 b- A project with an IRR = 20%, it has the following NCF (S) X X 4000 (SUS) 50,000 46.000 Find X? 6,500 8,000 45,000 15,000 15 years
Lesego Ltd is considering an investment in a new machine for the production of a new product, X. There are two possibilities, Machine A and Machine B. Both product X and the machine would have an expected life of five years.The following information is available:Product X Selling price $50Variable cost 32Increase in fixed overhead (excluding depreciation of the new machine) is $90,000 per year.YearSales units 1 10,0002 15,0003 20,0004 20,0005 5,000 Machine A Machine BInitial cost ($000) 550 480Residual value 50 30The company’s cost of capital is 10%,Required:Evaluate each machine, using the following methods:Accounting rate of return Payback;Net present value. Discuss the importance of capital budgeting in organisations.
Compute the equivalent uniform annual cost of the machine having the following data: Initial Cost = P100,000 Salvage Value = P20,000 Useful life = 20 years Rate of Interest = 12% Annual Operating Cost = P15,000
Two types of power converters are under consideration for a specific application. An economic comparison is to be made using a MARR of 10% and the following cost estimates: Alternative Model A Model B Service Life (Years) 5 10 First Cost $10,000 $20,000 Salvage Value 0 5,000 Annual Operating Cost 2,500 1,200 Draw the Cash Fiow Diagram for each alfernative covering the entire analysis period. Compute the Net Present Worth for Model A? Compute the Net Equivalent Uniform Annual Worth for Model A? Which of these alternatives should be selected?
Calculate the profitability of the following proposal using Return on investment method Proposal I Automatic machine Cost 420000 Estimated life 6.5 years Estimated sales p.a 175000 Cost : Material 60000 Labor 22000 Variable overheads 14000 a. 16.53% b. All the options are wrong c. 3.42% d. 4.62%

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