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- Draw the structures of the two linkage isomers; include representations of the resonance forms of the NO2- Explain the origin of and the differences in the position of both absorption maxima in the UV-visible spectra of the two isomers. Studies have shown the isomerization to be an intramolecular process. Comment on a possible mechanism. Draw a possible transition state for the isomerization process.Treatment of compound D with LiAlH4 followed by H2O forms compound E. D shows a molecular ion in its mass spectrum at m/z = 71 and IR absorptions at 3600–3200 and 2263 cm–1. E shows a molecular ion in its mass spectrum at m/z = 75 and IR absorptions at 3636 and 3600–3200 cm–1. Propose structures for D and E from these data and the given 1H NMR spectra.Treatment of compound D with LIAIH4 followed by H2O forms compound E. D shows a molecular ion in its mass spectrum at m/z = 71 and IR absorptions at 3600 – 3200 and 2263 cm-1. E shows a molecular ion in its mass spectrum at m/z = 75 and IR absorptions at 3636 and 3600 – 3200 cm-1. Propose structures for D and E from these data and the given 'H NMR spectra. 'H NMR of D 2H 2H 1H 8 7 6 2 ppm
- The infrared spectrum of the compound with the mass spectrum shown below has strong absorbances at 1482 cm, 1448 cm, and 770 cm²¹, Molecular ion peak: M = 120. 363 216 21 FIRA $13.3 13H 105 782 15.25 2263 100 ilo 120 Reprinted courtesy of the National Institute of Standards and Technology, U.S. Department of Commerce. Not copyrightable in the United States Which of the following structures is consistent with the data?Account for the following observations: (a) The 1H NMR spectrum of cyclohexane shows a single peak at room temperature, but when the temperate is lowered significantly the peak starts to broaden and then separates into two. (b) At room temperature, the 19F NMR spectrum of PF5 shows two lines, and even at the lowest experimentally accessible temperatures the spectrum is substantially unchanged. (c) In the 1H NMR spectrum of a casually prepared sample of ethanol a triplet and a quartet are seen. These multiplets show additional splittings if the sample is prepared with the careful exclusion of water.The 1H NMR spectrum, 13C NMR spectrum, mass spectrum, and IR spectrum below belong to a chemical with the molecular formula C4H9XO, where X is a halogen. Provide a structure for that compound. You must explain how you determined the structure for full credit based on the data bellow.
- A molecule of the molecular formula C5H11Br gives rise to the NMR spectrum below. When reacted with NaOH and water, it forms a product which by NMR has 2 protons 1H at 5.4 ppm and 1H at 5.5 ppm each having a J coupling of 17 Hz. (other protons also present) The product also has an IR stretch at 1550 cm1. Provide the structures of the starting material (1 pt) and product (2 pts) NaOH H20 C5H1,Br 6H triplet 4H quintet 1H quintet 10 8 7 6. 4 3 1 HSP-06-347 ppmThe tabulated 1H NMR and 13C NMR spectral data acquired for an unknown compound with an atomic composition of C11H20O2is detailed below. Using this data, propose a molecular structure for the unknown compound and, based on this structure, hypothesise a molecular structure of at least one major fragment appearing in the corresponding EI mass spectrum of the unknown compound, which is shown below; 1H NMR (500 MHz, Chloroform-d) δ 5.55 (s, 1H), 5.11 (d, J = 5.8 Hz, 1H), 4.16 (q, J = 6.3 Hz, 2H), 2.22 (d, J = 6.1 Hz, 2H), 2.18 (d, J = 6.1 Hz, 2H), 2.13 (s, 3H), 1.65 (s, 3H), 1.61 (s, 3H), 1.27 (t, J = 6.3 Hz, 3H). 13C NMR (125 MHz, Common NMR Solvents) δ 166.72 (C), 158.99 (C), 131.99 (C), 123.58 (CH), 116.45 (CH), 59.71 (CH2), 38.94 (CH2), 26.53 (CH2), 24.98 (CH3), 19.87 (CH3), 18.90 (CH3), 14.53 (CH3).Propose a structure for a compound that displays the given spectroscopic data. The molecular ion in the mass spectrum appears at m/z = 116. IR: 1710 (s) and 3000 (s, broad) cm¹. ¹H NMR: 8 = 0.94 (t, J = 7.0 Hz, 6H), 1.59 (m, 4H), 2.36 (quintet, J = 7.0 Hz, 1H) and 12.04 (broad s, 1H) ppm. 13C NMR: 8 = 11.7, 24.7, 48.7, and 183 ppm. Deduce the structure. Select 11 ||| ||| Q Search Draw C H O • Templates More Question Source: Vollhardt 7e - Organic Chemistry: Structure And Function P W Erase Publisher: W.H. Freeman ENG 4: 4/18
- Reaction of butanenitrile (CH3CH2CH2CN) with methylmagnesium bromide (CH3MgBr), followed by treatment with aqueous acid, forms compound G. G has a molecular ion in its mass spectrum at m/z = 86 and a base peak at m/z = 43. G exhibits a strong absorption in its IR spectrum at 1721 cm−1 and has the 1H NMR spectrum given below. What is the structure of G? We will learn about the details of this reaction in Chapter 22.(b) Determine the structure of an organic compound with a molecular ion at m/z 73 and absorption in its IR at 3300 (doublet) and 1680 cmWhich compound best matches the data given? D Mass Spec: Parent lon at 98 High Resolution Mass Spec gives: C6H100 IR: 3030, 2990, 2995, 1690 (strong), 1650 cm(small to medium band) A