The 0.20-kg particle has a speed v = 10.4 m/s as it passes the position shown. The coefficient of kinetic friction between the particle and the vertical-plane track is k = 0.16. Determine the magnitude of the total force exerted by the track on the particle. What is the change in speed i (positive if speeds up, negative if slows down) of the particle? Answers: p= 5.7 m 36°
The 0.20-kg particle has a speed v = 10.4 m/s as it passes the position shown. The coefficient of kinetic friction between the particle and the vertical-plane track is k = 0.16. Determine the magnitude of the total force exerted by the track on the particle. What is the change in speed i (positive if speeds up, negative if slows down) of the particle? Answers: p= 5.7 m 36°
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Transcribed Image Text:The 0.20-kg particle has a speed v = 10.4 m/s as it passes the position shown. The coefficient of kinetic friction between the particle
and the vertical-plane track is µ = 0.16. Determine the magnitude of the total force exerted by the track on the particle. What is the
HK
change in speed i (positive if speeds up, negative if slows down) of the particle?
Answers:
F =
i=
i
i
36
p= 5.7 m
N
m/s²
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