Testtube #1236V of DI H₂O1.00 ml2.00 ml3.00 ml4.00 mlV of Pb²+ (aq)5.50 ml6.30 ml4.00 ml3.00 ml2.00 ml1.00 ml2.50 ml1.20 mlV of I-(aq)5.00 ml5.00 ml5.00 ml5.00 ml2.00 ml2.50 ml[Pb²+ (aq)]V₂M₁=V₂M₂[(aq)]V₁M₁=V₂M₂[Pb²+ (aq)] = .004M [1(aq)], 0.005MQ = [Pb²+ (aq)]/([-(aq)])²Q=(.004M)( .005M)²Q=1.0x10-7Pbl₂ ppt?Appearance ofsolution in testtube.)

Answered: Image /qna-images/answer/9134caf7-95f2-44fd-8773-139d01f0880e.jpg

Test tube # 1 2 3 4 6 V of DI H₂O V of Pb2+ (aq) 1.00 ml 2.00 ml 3.00 ml 4.00 ml 5.50 ml 6.30 ml 4.00 ml 3.00 ml 2.00 ml 1.00 ml 2.50 ml 1.20 ml V of 1-(aq) 5.00 ml 5.00 ml 5.00 ml 5.00 ml 2.00 ml 2.50 ml [Pb²+ (aq)] V₁M₁=V₂M₂ [(aq)] V₁M₁=V₂M₂ [Pb2+ (aq)], .004M [H(aq)], 0.005M Q= [Pb²+ (aq)]/([-(aq)])² Q=(.004M)( .005M)² Q=1.0x107 Pbl₂ ppt? Appearance of solution in test tube.)

Test tube # 1 2 3 4 6 V of DI H₂O V of Pb2+ (aq) 1.00 ml 2.00 ml 3.00 ml 4.00 ml 5.50 ml 6.30 ml 4.00 ml 3.00 ml 2.00 ml 1.00 ml 2.50 ml 1.20 ml V of 1-(aq) 5.00 ml 5.00 ml 5.00 ml 5.00 ml 2.00 ml 2.50 ml [Pb²+ (aq)] V₁M₁=V₂M₂ [(aq)] V₁M₁=V₂M₂ [Pb2+ (aq)], .004M [H(aq)], 0.005M Q= [Pb²+ (aq)]/([-(aq)])² Q=(.004M)( .005M)² Q=1.0x107 Pbl₂ ppt? Appearance of solution in test tube.)

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter16: Applications Of Neutralization Titrations

Section: Chapter Questions

Problem 16.18QAP

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