Suppose you eat a breakfast snack that has 3 servings worth of food and that each serving is 750 calories. (1 Kilo-Calorie = 1000 calories). How much energy in terms of Joule would you get from eating the entire snack? (1Kilo-Calorie = 4184 Joule).
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- Suppose you eat a breakfast snack that has 3 servings worth of food and that each serving is 750 calories. (1 Kilo-Calorie = 1000 calories). How much energy in terms of Joule would you get from eating the entire snack? (1Kilo-Calorie = 4184 Joule).
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- A 46-kg woman eats a 522 Calorie (522 kcal) jelly doughnut for breakfast. (a) How many joules of energy are the equivalent of one jelly doughnut? 2192.4 X Your response is off by a multiple of ten. J (b) How many steps must the woman climb on a very tall stairway to change the gravitational potential energy of the woman-Earth system by a value equivalent to the food energy in one jelly doughnut? Assume the height of a single stair is 15 cm. 8.67 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. stairs (c) If the human body is only 26% efficient in converting chemical potential energy to mechanical energy, how many steps must the woman climb to work off her breakfast? 9 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. stairsOne ounce of a well-known breakfast cereal contains 99 Calories (1 food Calorie = 4186 J). If 2.4% of this energy could be converted by a weight lifter's body into work done in lifting a barbell, what is the heaviest barbell that could be lifted a distance of 2.0 m?A 62-kg woman eats a 620 Calorie (620 kcal) jelly doughnut for breakfast. (a) How many joules of energy are the equivalent of one jelly doughnut? 2594080 (b) How many steps must the woman climb on a very tall stairway to change the gravitational potential energy of the woman-Earth system by a value equivalent to the food energy in one jelly doughnut? Assume the height of a single stair is 15 cm. 27893 stairs (c) If the human body is only 27% efficient in converting chemical potential energy to mechanical energy, how many steps must the woman climb to work off her breakfast? 75.2 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. stairs Need Help? Read It
- 6. A 55-kg woman cheats on her diet and eats a 540-Calorie (540 kcal) jelly doughnut for breakfast. (a) How many joules of energy are equivalent of one jelly doughnut? (b) How many stairs must the woman climb to perform an amount of mechanical energy work equivalent to the food energy in one jelly doughnut? Assume the height of a single stair is 15 cm. (c) If the human body is only 25% efficient in converting chemical energy into mechanical energy, how many stairs must the woman climb to work off her breakfast?The human body is not perfectly efficient. In fact, only about 20% of the Calories we consume are used for mechanical work (i.e., moving the body around). Estimate how many granola bars (150 Cal per bar) an 85 kg person will burn if they climb vertically up the side of the Empire State Building. height of Empire State Building, h = 443 m unit conversion: 1 Cal = 4184 JoulesA person consumes about 2600 Cal a day. 1 Cal = 4186 J, and 1 kWh = 860 Cal. What is this energy in kilowatt-hours? Express your answer using two significant figures.
- Suppose we have a piece of a candy bar that has an initial mass of 28g. If we ignite the piece of candy bar (literally burn it), and it increases the temperature of 393.86g of water from 21.71°C to 78.73°C, how many calories per gram of energy did the candy bar provide if the final mass of the marshmallow is 4.33? Note: 1.00 cal = 4.184 J. Give your answer in units of cal/g.A student is trying to find the energy it takes to melt an ice cube. They measure exactly 95.1 mL of water and pour it into a styrofoam cup. They use a thermometer to find the initial temperature is 23.8 °C, and then drop an ice cube in the water, covering it and stirring until it is completely melted. After it has melted, the water cools to a final temperature of 16.5 °C. How much energy (in calories) did it take to melt this ice cube? Note: The density of water is 1.0 g/mL and the specific heat of water is 1.0 cal/(g·°C)Suppose we have a piece of a candy bar that has an initial mass of 28g. If we ignite the piece of candy bar (literally burn it), and it increases the temperature of 338.09g of water from 16.3°C to 73.87°C, how many calories per gram of energy did the candy bar provide if the final mass of the marshmallow is 2.76? Note: 1.00 cal = 4.184 J.
- Before brewers had access to propane or natural gas, they would heat large, insulated vats of water by adding hot stones to the water. The stones are heated to 800°C before they are dropped into a particular well-insulated large vat holding 1,200 kg of water at 20°C. If we want to heat the water to 70°C, what mass of stones must be added the the vat? The specific heat of the stone is about 790 J/kg°C and the specific heat of water is 4,186 J/kg°C. Assume the mass of the water does not change and that the vat is a perfect insulator so no internal energy is lost to 6. 9When it rains, water vapor in the air condenses into liquid water, and energy is released. (a) How much energy is released when 0.0318 m (1.25 inch) of rain falls over an area of 2.59×106 m² (one square mile)? (b) If the average energy needed to heat one home for a year is 1.50x1011 J, how many homes could be heated for a year with the energy determined in part (a)? (a) Number (b) Number i i Units Units >I have a bucket of icewater with 100 grams of ice and 900 grams of liquid water all at zero degrees Celcius. I throw a hot chunk of iron into it (after which no heat enters or escapes the system), and the final temperature is 100 degrees Celcius with the ice having melted and some of the water actually boiling. The mass of the iron is 473 grams, and its initial temperature is 7,646 degrees Celcius. How many grams of water actually boil? (Don't write the unit, just the number.) You'll need these numbers: Specific heat of water: 4.2 J/g/deg Specific heat of iron: 0.46 J/g/deg Heat of fusion of water: 340 J/g Heat of Vaporization of water: 2300 J/g