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Suppose x has a distribution with u = 19 and o = 14. A USE SALT (a) If a random sample of size n = 33 is drawn, find u, o, and P(19 < x< 21). (Round o, to two decimal places and the probability to four decimal places.) P(19 < x < 21) = (b) If a random sample of size n = 66 is drawn, find u, o and P(19 < x < 21). (Round o to two decimal places and the probability to four decimal places.) 『ス= P(19 < x< 21) =

Suppose x has a distribution with u = 19 and o = 14. A USE SALT (a) If a random sample of size n = 33 is drawn, find u, o, and P(19 < x< 21). (Round o, to two decimal places and the probability to four decimal places.) P(19 < x < 21) = (b) If a random sample of size n = 66 is drawn, find u, o and P(19 < x < 21). (Round o to two decimal places and the probability to four decimal places.) 『ス= P(19 < x< 21) =

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.8: Probability
Problem 31E
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Suppose x has a distribution with u = 19 and o = 14. n USE SALT (a) If a random sample of size n = 33 is drawn, find u, o , and P(19 < x < 21). (Round o, to two decimal places and the probability to four decimal places.) 阪= 『ス= P(19 < x s 21) = (b) If a random sample of size n = 66 is drawn, find u, o, and P(19 < x< 21). (Round o, to two decimal places and the probability to four decimal places.) 『ス= P(19 < x < 21) = (c) Why should you expect the probability of part (b) to be higher than that of part (a)? (Hint: Consider the standard deviations in parts (a) and (b).) The standard deviation of part (b) is ---Select--- O part (a) because of the ---Select--- O sample size. Therefore, the distribution about u, is ---Select--- O
Transcribed Image Text:Suppose x has a distribution with u = 19 and o = 14. n USE SALT (a) If a random sample of size n = 33 is drawn, find u, o , and P(19 < x < 21). (Round o, to two decimal places and the probability to four decimal places.) 阪= 『ス= P(19 < x s 21) = (b) If a random sample of size n = 66 is drawn, find u, o, and P(19 < x< 21). (Round o, to two decimal places and the probability to four decimal places.) 『ス= P(19 < x < 21) = (c) Why should you expect the probability of part (b) to be higher than that of part (a)? (Hint: Consider the standard deviations in parts (a) and (b).) The standard deviation of part (b) is ---Select--- O part (a) because of the ---Select--- O sample size. Therefore, the distribution about u, is ---Select--- O
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