String[] name={"John", "Mary", "Jim", "Sam"}; Which choice is correct? Group of answer choices name.get(1)="John" name.get(1)="Mary" name[1]="John" name[1]="Mary"
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String[] name={"John", "Mary", "Jim", "Sam"};
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- Doctor -signature:String -doctorID:int - medicine:Arraylist +Doctor(signature:String,doctorID:int) +PrescribeMedicine():void + salary () +checkRecords():void Medicine Pharmacist -medName:String -startTime:int -dosage :int -endTime:int -date_prescribed:int - medicine:Arraylist +Medicine(medName:String,-dosage :int,date_prescribed:int) +Pharmacist (startTime:int,endTime:int) +checkForConflict():double +confirm_prescription():String +getStartTime():int +getEndTime():int +setStartTime(time:int):void +setEndTime(time1:int).voidion C Lons Employee -id: int -name String - dob : Date -staff : ArrayList +setid(int): void +getld() : int +setName(String): void +setDob(Date) : void +getDob(): Date +addStaff(Employee) : void +getStaff() : ArrayListLibrary class: Fields: books as arraylist to store all the books available in the library B3 B1 B2 В4 B5 Constructor: Library() } : No parameterized constructor to create the books object Methods: 1. addBook(Book bookobj): to add a new book to the arraylist; send the book object as a parameter to this method. 2. searchBook(String name): search a book by a given name in the arraylist. if exits print bookX found; otherwise print not found!!! 3. RemoveBook(String name): to delete a book object from arraylist by a given name: Hint: you need to use iterator class and remove method. Book class: Fileds: bookld, bookname. Constructor: two parameterized constructor that accepts name a parameter Book(int ID, String name) ..... Methods: 1. Accessor method to return the name of the book 2. Mutator method to change the id of the book. Use this Main method: in your program: public static void main(String args[]) { Library lib=new Library(); lib.addBook(new Book("b1")); lib.addBook(new Book("b2"));…
- Trace through the following program and show the output. Show your work for partial credit. public class Employee { private static int empID = 1111l; private String name , position; double salary; public Employee(String name) { empID ++; this.name 3 пате; } public Employee(Employee obj) { empID = obj.empĪD; пате %3D оbj.naте; position = obj.position; %3D public void empPosition(String empPosition) {position = empPosition;} public void empSalary(double empSalary) { salary = empSalary;} public String toString() { return name + " "+empID + " "+ position +" $"+salary; public void setName(String empName){ name = empName;} public static void main(String args[]) { Employee empOne = new Employee("James Smith"), empTwo; %3D empOne.empPosition("Senior Software Engineer"); етрOпе.етpSalary(1000); System.out.println(empOne); еmpTwo empTwo.empPosition("CEO"); System.out.println(empOne); System.out.println(empTwo); %3D етpОпе empOne ;PLEASE HELP ME! ? Maximize and use alternative method to this code! package com.btech.pf101; import java.io.bufferedreader; import java.io.inputstreamreader; import java.util.calendar; import java.util.date; public class pawnshopcode { private static final bufferedreader br = new bufferedreader(new inputstreamreader(system.in)); private static string name; private static int age; private static string address; private static string contactno; private static int itemtype; private static string itemtypename; private static final int itemtype_gagdet = 1; private static final int itemtype_jewelry = 2; private static final int itemtype_musicinstrument = 3; private static final int itemtype_homeequipment = 4; private static final int itemtype_landtitle = 5; private static string itemdescription; private static int periodtype; private static string periodtypename; private static final int periodtype_days = 1; private…function myChoice(items) {if (!this.value && !this.items) {this.items = items[0];} else if (!this.value || (params.length > 0 && params[0] == "rechoose")) {let index = Math.floor(Math.random() * (this.items.length - 0)) + 0;this.value = this.items[index];return this.value;}return this.value;} var a = myChoice([1, "a", 3, false]);console.log(myChoice(3, 12));console.log(myChoice(51, -2));console.log(myChoice("happy", false));console.log(myChoice([1, 2, 3]));console.log(myChoice("rechoose"));console.log(myChoice(a, a)); these are directions and examples myChoice( items ) This function accepts a list of items as input and creates a function that returns a randomly-chosen item. After choosing a random item, that same item will be always be returned, regardless of the functions input, with one exception. If the first input is the string 'rechoose', then a new random item will be chosen and therafter returned. this is KEYYYY!! Examples var a = myChoice( [1, "a", 3, false]…
- $marks = array( "Sara" => array( "Programming" => 95, "DataBase" => 85, "Web" => 74, ), "Diana" => array( "Programming" => 78, "DataBase" => 98, "Web" => 66, ), "Amy" => array( "Programming" => 88, "DataBase" => 76, "Web" => 99, ), ); 1 : sort the array by the name of student from A-Z; 2 : search if Ram is exist :if exiset print the value; else : student does not exist 3 : calculate the avg of each student and print it as :the avg for Sara is : 84.66dictionaries = []dictionaries.append({"First":"Bob", "Last":"Jones", "Color":"red"})dictionaries.append({"First":"Harpreet", "Last":"Kaur", "Color":"green"})dictionaries.append({"First":"Mohamad", "Last":"Argani", "Color":"blue"})for i in range(0, -1,len(dictionaries)):print(dictionaries[i]['First']) ******************** Please modify the code, so the result will show first, last names and colour separated by a single spacePython Data = { "logs": [ { "logType": “xxxxx” }, { "logType": “43435” }, { "logType": “count” }, { "logType": “4452” }, { "logType": “count” }, { "logType": “count” }, { "logType": “43435” }, { "logType": "count" }, { "logType": "count" } ] } So, please count the total of "logType": “count” My desired output: { "count”: 5 }
- Part 2. fill Method Define a method in simpy named fill. Its purpose is to fill a simpy's values with a specific number of repeating values. The fill method will have two parameters following self: 1. The float value you are filling the values list in with. 2. The int number of values to fill in. The fill method is procedure-like in that it returns None and mutates the object the method is called on. After calling fill, the length of the Simpy object's values should be equal to the second argument given to fill. For example, consider the following usage and expected printed output, given inline, below: twos = Simpy([]) twos.fill(2.0, 3) print("Actual: ", twos, Expected: Simpy([2.0, 2.0, 2.0])") twos.fill(2.0, 5) print("Actual: ", twos, " - Expected: Simpy([2.0, 2.0, 2.0, 2.0, 2.0])") mixed = Simpy([]) mixed.fill(3.0, 3) - Expected: Simpy([3.0, 3.0, 3.0])") print("Actual: ", mixed, mixed.fill(2.0, 2) print("Actual: ", mixed, Expected: Simpy ([2.0, 2.0])") PythonImplement all the classes using Java programming language from the given UML Class diagram. Note: This problem requires you to submit just two classes: Customer.java, Account.java. Do NOT include "public static void main()" method inside all of these classes. Graders will be testing your classes, using the unit-testing framework JUnit 4. Customer - ID:int -name:String -gender:char 'm' or 'f' +Customer(ID:int,name:String, discount:int) +getID():int +getName ():String +getGender ():char +toString():String "name (ID)" The Customer class models, customer design as shown in the class diagram. Write the codes for the Customer class and a test driver to test all the public methods. AccountWhat sort algorithm is implemented in the sortArray1 method in the following program segment? *