Solve for Vo in the electrical circuit using mesh analysis.
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Solve for Vo in the electrical circuit using mesh analysis.
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- VIN = 5.3V. Determine Io1 (in mA) ? %3D 20 K2 30 k2 I0Krz a. 0.325 Voi O b. -0.397 C. -0.325 40kz op amp #! o d. ±25 p amp #2 e. 0.397The true value of a current is 10mA and it is indicated with a digital ammeter as 12mA. The absolute error for this measurement system is mA. O a. 2 O b. 0.16 C. -2 O d. 0.2Consider the circuit below. The frequency of oscillation is: www OF R₂ 1,0 ΚΩ C₁ 0.015 μF R₁ 1.0 ΚΩ 11 L Q₁ 2N5458 C₂ 0.015 μF 10.6 kHz 1.94 kHz 19.4 kHz 15.9 kHz www R₁ 10 ΚΩ R3 820 02 ww R₁ 10 ΚΩ ovour D₁ IN914 C3 1.0 με
- In a tansistor, IC= 100 mA and IE = 100.2 mA. The value of ß is ............ O 100 O 200 50 O about to1If the diode for the given circuit below is a Silicon diode, how much is the maximum positive voltage (taken at the series connection of the diode and the battery)? R1 1 V1 1k2 D1 7.5V Vout 1kHz 4. 0° V2 - T 3.6V Answer: 루Ex: The output Voltage of a Tx is given 500(1+0.4 Sin 31402) Sin 6.28 × 10²t. This voltage is fed to a load of 60052. Determine (i) fc (ii) for (iii) P (iv) P
- Calculate the missing value: P = 1000 W, E = 1 = 20 A. a. 0.02 V O b. 50 V O c. 500 V O d. 20,000 VBand 1 GR R y BU G GR BN G Band 2 R W V V GR BU R GR W BU Band 3 BN R BL S R R BL GO BL R Table 1 Resistor Color Codes and Measurements Band 4 GO 60 GO GO GO GO GO GO GO GO Band 5 Theoretical value R Plus Tolerance 8205% 8612 3 900±5% 40952 3705 27 2±5% 28-35 25-65 0.47±5% 0-493552 0.44651 71402 6800 ± 5% 5600 55880 82nt 5% 1-82±5% 86-1-22 1.892 R Minus Tolerance 39 150 40.952 56001 ± 540 5880 Measured Value 7792 8012 38542 26 0.45 6460 6630 53201 5570 77-92 80.5 #1.712 37.05~ 5320 2 1.82 39.25 5520 MAKE A CONCLUSION FOR THIS (8 SENTENCES ONLY) The content must be the connection of resistor color codes to tolerances and the relationship of the measured value to the theoretrical valueEXPLAIN THE OPERATION OF THE CIRCUIT SHOWN IN FIGURE +5V 1ΚΩ 1ΚΩ 1ΚΩ ΙΚΩ 1ΚΩ 5 4 7 6 9 8 11 10 + +5V /+1) Α + + 3 12 14 13 IM339 100ΚΩ Μ Μ Μ 1 ΚΩ Τ 1 ΚΩ ΙΚΩ ΙΚΩ Thermistor/ LDR
- Find the Cea for the circuit given below: C C C C O 20 O 2.5C O 10 O 1.5CIf the measured values of R1 = 323.1 Q, R2 = 324.2 Q and R3 = 324.7 Q, calculate the difference in measured R compared to your calculation of equivalent R in Ohms? KIT NO. 1PASCO EM-8622 SCIentfic CYRCUIT EXPERIMENT TENMA 72-7780 1079 A C Auto Range 6000 Counte True RMS Multimeter ANGE MAX/MIN RELA Hz/% DILIGHT SELECTIVR.C Hz% mA H Am Hz% ONCV 60A. CE A (10mviA) VOHZC ww COM FUSED FUB RIInductive Circuits Fill in all the missing values. Refer to the following formulas: XL=2fLL=XL2ff=XL2L Inductance (H) Frequency (Hz) Inductive Reactance ( ) 1.2 60 0.085 213.628 1000 4712.389 0.65 600 3.6 678.584 25 411.459 0.5 60 0.85 6408.849 20 201.062 0.45 400 4.8 2412.743 1000 40.841