Situation 4] From the given data ofa dlosed traverse, The adjusted bearing of BC using compassrule. The adjusted bearing of DA using compass rule. The total area using Coordinates method. The total area using Double Parallel Distance method. i. ii. ii. iv. Distance, m 368.76 Bearing N15°18'E Line AB S85046'E S18030'W BC 645.38 467.86 593.00 CD DA N77035W

Situation 4] From the given data ofa dlosed traverse, The adjusted bearing of BC using compassrule. The adjusted bearing of DA using compass rule. The total area using Coordinates method. The total area using Double Parallel Distance method. i. ii. ii. iv. Distance, m 368.76 Bearing N15°18'E Line AB S85046'E S18030'W BC 645.38 467.86 593.00 CD DA N77035W

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Q3: A: Draw the diagram of traverse classification. B: In closed traverse ABCD. The partial coordinates were known as shown below. Determine its area by DMD method. 04 N Dofland OWODY dienstl it with (nm) dinostim Mem. AB BC CD DA ΔΧ 40 -80 -50 AY 60 100 -70
3. The following data if a closed traverse is shown in the technical description. The area of the closed traverse is 63147.05 sq. m. LINES AB BC CD LAT. a -240.20 -160.00 DA 179.70 Solve for the unknown variables. DEP. 120 с e -220 DMD b d f 8 2A 26460.0 X -86480.0 39534.0
PROBLEM 1. Given in the accompanying tabulation are the adjusted latitude and adjusted departure of a closed traverse. Calculate the area by the DMD method LINE ADJ ADJ LAT DEP AB - 125.055 + 196.387 BC +20.241 + 241.003 CD +180.107 + 65.326 DE +210.169 - 104.519 EF -74.003 - 260.516 FA - 211.459 - 137.681
8. Compute for the following and show the tabulated solutions: Azimuth LINES Length (S) АВ 1020.87 168d35m ВС 1117.26 263d30m CD 660.08 304d25m DE 495.85 5d30m EF 850.62 46d15m FA 855.45 112d30m (lengths in 3 dec. places; bearings in deg-mm-ss) a. Using Transit Rule, solve for adjusted latitudes, departures, distances, and bearings for all the traverse lines Lines Adj. Latitude Adj. Departure Adj. Length Adj. Bearing AB BC CD DE EF FA
Q7) Calculate the coordinates. Check whether the error is acceptable. Make corrections. N 59.0701g S2 145.5558g S1 161.51849 A x=315.122m $3 S6 120.6210g 167.8089g S4 F S5 Y (m) x (m) Дх B (grad) a (grad) S (m) Ay STATION A 137.619 214.077 170.542 D 189.664 225.219 F 156.907 A 8 y=74.056m
From the following measured interiror angles of a five sided figure, compute the following: Station Values of Angles (No. of Measurements A 110.00 98.000 108.00 120.00 105.00 BUDE с 5 NOTE: Final answer must be in decimal degrees. HINT: Sum of Interior Angles = (n-2)*180* NAO сл 6 4 2 1 a) Probable value of Angle A. b) Probable value of Angle C. °c) Probable value of Angle D
ANSWER KEY=D 108.1502m∆h 22.4596m
Situation 4] From the given data of a closed traverse, The adjusted bearing of BC using compass rule. The adjusted bearing of DA using compass rule. The total area using Coordinates method. The total area using Double Parallel Distance method. i. ii. iii. iv. Distance, m 368.76 Line Bearing N15°18'E AB BC CD S85046'E S18030W N77035W 645.38 467.86 DA 593.00
V;19 | ZAO N O o GOX U | KOREK Traverse_ho... 0:- The table below shows the ficld measurements for a traverse A, B.C. D, E, if the Azimuth of AB = 290" and the coordinate of point A (1000, 1000) . Calculate the coordinates of all stations of the traverse. Point Line Length(m) Azimuth Angle to the right A AB 50 290 B 90 BC 65 95 CD 61 D 120 DE 50 E A
I. Determine the interior angles of each stations and azimuths for each surveying lines. AZAB = INTZA = 40 40P 37 AZBC = INTZB = C 30 22 AZCD = INTZC = 66° 40' AZDE = INTZD = 15° 12 1s° 58 AZEA = INTZE =
Using the data below, compute for the Linear Error of Closure Also, Determine the adjusted latitude and departure using compass rule: Line Distance Latitude Departure Adjustment (Lat) Adjustment (Dep) Adjusted Lat Adjusted Dep 1-2 388.08 -234.363 -309.322 2-3 732.72 732.665 8.952 3-4 324.78 -22.938 323.969 4-1 477.24 -476.557 -25.531 Express all answer unitless and with 3 decimals for A to J Next
Q3): The following data were collected while running a closed traverse ABCDA. Calculate: 1- Coordinates of B (Easting and Northing). N Line AB BC CD DA 4- 5- Distance BC and CD. 6- Coordinates of C (Easting and Northing). Interior angles A and B Length(m) 330 827 Sum= 2435.15 Azimuth 181°25' 89°50' 355°00' 264°18'20" Point A B C D A (calculated) = Easting 500 B 1323.167 Northing 500 582.059 A= B= Angles