shown in the Vps low is Write the FORMULA for the total impedance of the circuit Zut= R²+ cL- Write the FORMULA for the phase of the total impedance of the circuit -tan-12 R Determine the numerical value of Z-2090.5 Determine the numerical value of 41 Determine the current through the circuit: PEAK)-4818-3 (RMS)-3.404E-3 • Vn(RMS)-5.22 R ww Determine the voltage across the resistor: VPEAK-7.387 ✔Amps ✔Amps O a high-pass filter O an inductive rectifier x Voits x Voits Determine the voltage across the inductor: V(PEAK)-0184 V(RMS)-[6.40 ✔ Voits ✔Voits irce. The AC power source has an O a radio tuner O a phase conjugate deflector If a second circuit were connected in parallel with the inductor, this circuit would be considered as: O a low-pass filter O a capacitive switcher ✓degrees x HZ. The resistor has a

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13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Shown in the figure below is an "RL" circuit drive by an AC power source. The AC power source has an RMS voltage of Vps (RMS) = 9.84 Volts and is running at a frequency of f = 8.585e+04 Hz. The resistor has a resistance of R = 2170 and the inductor has an inductance of L = 3.54e-03 Henries.
Vps
R
ww
Write the FORMULA for the total impedance of the circuit Ztot =
Determine the numerical value of Ztot = 2890.5
Determine the numerical value of $z= = 41
Determine the current through the circuit:
• I(PEAK) = 4.81E-3
• I(RMS) = 3.404E-3
Determine the voltage across the resistor:
• VR(PEAK) = 7.387
• VR(RMS) = 5.22
✔✔ Amps
✔Amps
Write the FORMULA for the phase of the total impedance of the circuit z... = | tan-1 2701
R
x Volts
X Volts
Determine the voltage across the inductor:
• VL(PEAK) = 9.184
• VL(RMS) = 6.49
✔ Volts
Volts
L
R²+ WL-
✔ degrees
2
If a second circuit were connected in parallel with the inductor, this circuit would be considered as:
O a low-pass filter
O a capacitive switcher
O a high-pass filter
O an inductive rectifier
O a radio tuner
O a phase conjugate deflector
NOTE: In your formulas, use variables R, w, and L. Do not use f.
X
Transcribed Image Text:Shown in the figure below is an "RL" circuit drive by an AC power source. The AC power source has an RMS voltage of Vps (RMS) = 9.84 Volts and is running at a frequency of f = 8.585e+04 Hz. The resistor has a resistance of R = 2170 and the inductor has an inductance of L = 3.54e-03 Henries. Vps R ww Write the FORMULA for the total impedance of the circuit Ztot = Determine the numerical value of Ztot = 2890.5 Determine the numerical value of $z= = 41 Determine the current through the circuit: • I(PEAK) = 4.81E-3 • I(RMS) = 3.404E-3 Determine the voltage across the resistor: • VR(PEAK) = 7.387 • VR(RMS) = 5.22 ✔✔ Amps ✔Amps Write the FORMULA for the phase of the total impedance of the circuit z... = | tan-1 2701 R x Volts X Volts Determine the voltage across the inductor: • VL(PEAK) = 9.184 • VL(RMS) = 6.49 ✔ Volts Volts L R²+ WL- ✔ degrees 2 If a second circuit were connected in parallel with the inductor, this circuit would be considered as: O a low-pass filter O a capacitive switcher O a high-pass filter O an inductive rectifier O a radio tuner O a phase conjugate deflector NOTE: In your formulas, use variables R, w, and L. Do not use f. X
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