Show your work, use general chemistry rules for significant figures. 6. A solution is made by dissolving 1.0 x 10–4 mol of Na3PO4 in 200.00 mL of water. Then 0.25 mL of 0.200 F HCl is added to the solution. H3PO4 ⇌ H+ + H2PO4–                               Ka1 = 7.11 x 10–3     H2PO4– ⇌ H+ + HPO42–                             Ka2 = 6.34 x 10–8 HPO42– ⇌ H+ + PO43–                               Ka3 = 4.17 x 10–13 (a)  What is the pH of the resultant solution? (b) An additional 0.75mL of 0.200 F HCl is added to the solution from the end of part (a). What is the pH of the resultant solution? (c) Finally, an additional 0.50 mL of 0.200 F HCl is added to the solution from the end of part (b). What is the pH of the resultant solution?

Chemistry & Chemical Reactivity
9th Edition
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Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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Chapter16: Principles Of Chemical Reactivity: The Chemistry Of Acids And Bases
Section: Chapter Questions
Problem 73PS: Hydrazine, N2H4, can interact with water in two steps. N2H4(aq) + H2O() N2H5+(aq) + OH(aq) Kb1 =...
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Show your work, use general chemistry rules for significant figures.

6. A solution is made by dissolving 1.0 x 10–4 mol of Na3PO4 in 200.00 mL of water. Then 0.25 mL of 0.200 F HCl is added to the solution.

H3PO4 ⇌ H+ + H2PO4                               Ka1 = 7.11 x 10–3    

H2PO4– ⇌ H+ + HPO42–                             Ka2 = 6.34 x 10–8

HPO42– ⇌ H+ + PO43–                               Ka3 = 4.17 x 10–13

(a)  What is the pH of the resultant solution?

(b) An additional 0.75mL of 0.200 F HCl is added to the solution from the end of part (a). What is the pH of the resultant solution?

(c) Finally, an additional 0.50 mL of 0.200 F HCl is added to the solution from the end of part (b). What is the pH of the resultant solution?

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