Homework Help is Here – Start Your Trial Now!
Science
Chemistry
Sample Exercise 4: Calculation of molality and Molarity A solution is made by dissolving 4.35 g glucose (C6H₁2O6) in 25.0 mL of water at 25 °C. Calculate the (a) molality and (b) the Molarity of glucose in the solution. Water has a density of 1.00 g/mL. The glucose solution has a density of 1.046 g/mL. Solution (a) Calculating molality requires that we know the mass of both components separately. We then use the MM of the solute to get the moles of solute. mass H₂O: = 25.0 g H₂O MM C6H₁2O6 = 180.16 g/mol 25.0 mL x 1.00 g =

Sample Exercise 4: Calculation of molality and Molarity A solution is made by dissolving 4.35 g glucose (C6H₁2O6) in 25.0 mL of water at 25 °C. Calculate the (a) molality and (b) the Molarity of glucose in the solution. Water has a density of 1.00 g/mL. The glucose solution has a density of 1.046 g/mL. Solution (a) Calculating molality requires that we know the mass of both components separately. We then use the MM of the solute to get the moles of solute. mass H₂O: = 25.0 g H₂O MM C6H₁2O6 = 180.16 g/mol 25.0 mL x 1.00 g =

Introduction to General, Organic and Biochemistry
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter6: Solutions And Colloids
Section: Chapter Questions
Problem 6.111P: 6-111 As noted in Section 6-8C, the amount of external pressure that must be applied to a more...
See similar textbooks
icon
Related questions
Question
Sample Exercise 4: Calculation of molality and Molarity A solution is made by dissolving 4.35 g glucose (C6H₁2O6) in 25.0 mL of water at 25 °C. Calculate the (a) molality and (b) the Molarity of glucose in the solution. Water has a density of 1.00 g/mL. The glucose solution has a density of 1.046 g/mL. Solution (a) Calculating molality requires that we know the mass of both components separately. We then use the MM of the solute to get the moles of solute. mass H₂O: = 25.0 mL x 1.00 g 25.0 mL x mL moles glucose: 1.00 g = 25.0 g H₂O MM C6H₁₂O6 = 180.16 g/mol 4.35 g 180.16 g mol-¹ = 0.024145 mol C6H₁2 06 molality glucose: 0.024145 mol = 0.966 m 0.0250 kg H₂O Molarity glucose: (b) To get the Molarity of the glucose in the solution, we need to know the mass of the solution, then use the solution density to find the volume of the solution. mass of solution: mass H₂O + mass glucose = 25.0 g + 4.35 g = 29.35 g volume of solution: 29.35 g x 1 mL = 28.06 mL of sol'n 1.046 g = 0.860 M 0.024145 mol 0.02806 L sol'n
Transcribed Image Text:Sample Exercise 4: Calculation of molality and Molarity A solution is made by dissolving 4.35 g glucose (C6H₁2O6) in 25.0 mL of water at 25 °C. Calculate the (a) molality and (b) the Molarity of glucose in the solution. Water has a density of 1.00 g/mL. The glucose solution has a density of 1.046 g/mL. Solution (a) Calculating molality requires that we know the mass of both components separately. We then use the MM of the solute to get the moles of solute. mass H₂O: = 25.0 mL x 1.00 g 25.0 mL x mL moles glucose: 1.00 g = 25.0 g H₂O MM C6H₁₂O6 = 180.16 g/mol 4.35 g 180.16 g mol-¹ = 0.024145 mol C6H₁2 06 molality glucose: 0.024145 mol = 0.966 m 0.0250 kg H₂O Molarity glucose: (b) To get the Molarity of the glucose in the solution, we need to know the mass of the solution, then use the solution density to find the volume of the solution. mass of solution: mass H₂O + mass glucose = 25.0 g + 4.35 g = 29.35 g volume of solution: 29.35 g x 1 mL = 28.06 mL of sol'n 1.046 g = 0.860 M 0.024145 mol 0.02806 L sol'n
Expert Solution
steps

Step by step

Solved in 4 steps with 13 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Solutions
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Introduction to General, Organic and Biochemistry
Introduction to General, Organic and Biochemistry
Chemistry
ISBN:
9781285869759
Author:
Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:
Cengage Learning
Principles of Modern Chemistry
Principles of Modern Chemistry
Chemistry
ISBN:
9781305079113
Author:
David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:
Cengage Learning
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
General, Organic, and Biological Chemistry
General, Organic, and Biological Chemistry
Chemistry
ISBN:
9781285853918
Author:
H. Stephen Stoker
Publisher:
Cengage Learning
Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
Chemistry
ISBN:
9781337399074
Author:
John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:
Cengage Learning
Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
Chemistry
ISBN:
9781133949640
Author:
John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:
Cengage Learning
SEE MORE TEXTBOOKS