Rigid bar ABC is supported by two aluminum alloy (E = 10,000 ksi) rods as shown below. The horizontal distance between rods (1) and (2) is a = 120 in. Rod (1) has a length of £1 = 87 in. and a cross-sectional area of A1 = 0.65 in.2. Rod (2) has a length of £2 = 84 in. and a cross-sectional area of A2 = 1.15 in.2. Rigid bar ABC is to remain horizontal under a load of P = 25 kips. Determine the distance x (in inches rounded to the nearest tenths) from joint A to the location of load P so that bar ABC remains horizontal. L₁ (1) X a B P (2) C L2

Rigid bar ABC is supported by two aluminum alloy (E = 10,000 ksi) rods as shown below. The horizontal distance between rods (1) and (2) is a = 120 in. Rod (1) has a length of £1 = 87 in. and a cross-sectional area of A1 = 0.65 in.2. Rod (2) has a length of £2 = 84 in. and a cross-sectional area of A2 = 1.15 in.2. Rigid bar ABC is to remain horizontal under a load of P = 25 kips. Determine the distance x (in inches rounded to the nearest tenths) from joint A to the location of load P so that bar ABC remains horizontal. L₁ (1) X a B P (2) C L2

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter1: Tension, Compression, And Shear

Section: Chapter Questions

Problem 1.4.9P: Two steel wines support a moveable overhead camera weighing W = 28 lb (see figure part a) used For...

See similar textbooks

Similar questions

Rigid bar ABC is supported by two aluminum alloy (E = 10,000 ksi) rods as shown below. The horizontal distance between rods (1) and (2) is a = 150 in. Rod (1) has a length of L₁ = 99 in. and a cross-sectional area of A₁ = 0.55 in.². Rod (2) has a length of L₂ = 96 in. and a cross-sectional area of A₂ = 0.95 in.². Rigid bar ABC is to remain horizontal under a load of P = 35 kips. Determine the distance x from joint A to the location of load P so that bar ABC remains horizontal. L Answer: X= i (1) eTextbook and Media Save for Later x in. B (2) L2 Attempts: 0 of 5 used Submit Answer
A compound steel (E = 30,000 ksi) bar is subjected to the loads shown. Bar (1) has a cross-sectional area of A₁ = 0.45 in.² and a length of L₁ = 85 in. Bar (2) has an area of A₂ = 0.45 in.² and a length of L2 = 80 in. Bar (3) has an area of A3 = 0.19 in.² and a length of L3 = 40 in. The loads and angles are P = 24 kips, a = 30°, Q = 10 kips, ß = 56°, and R = 11 kips. Determine the vertical deflection of end A. P B D B A (1) (2) VR U O L₁ L2 L3
A compound steel (E = 30,000 ksi) bar is subjected to the loads shown. Bar (1) has a cross-sectional area of A₁ = 0.40 in.² and a length of L₁ = 120 in. Bar (2) has an area of A₂ = 0.40 in.² and a length of L₂ = 100 in. Bar (3) has an area of A3 = 0.13 in.² and a length of L3 = 35 in. The loads and angles are P = 26 kips, a = 39%, Q = 14 kips, B = 61°, and R = 12 kips. Determine the vertical deflection of end A. A downwards deflection is positive, while an upwards deflection is negative. D (1) L₁ (2) Answer: ỖA = i B A R L2 L3 in.
( 48ll O O 2 9:YV The rod BD is made of material with G1= 135 GPa has a diameter 16 mm is bonded to the tube CA at point B, the tube made of material with G2=230 GPa has an outer diameter 37 mm and wall thickness of 7 mm. If T1=803 N.m and T2=1445 N.m, answer the following questions: A B T2 N-m 0.4 m 0.1 m 0.3 m T1 N-m The polar moment of inertia of the rod BD is Your answer The polar moment of inertia of the tube CA is
6. Three wires are used to support the 150-lb force. The wires AB and AC are made of steel, and wire AD is made of copper. Assume that the three wires have constant cross-sectional area A = 0.0123 in?. For steel wire, a = 8 x 10 in/ (in°F ) and E = 29000 ksi and for copper wire, a = 9.6 x 10 in/ (in°F ) and E = 17000 ksi. Calculate the axial force exerted by the three wires if the temperature is raised by 80°F. Answer: Pu= 10 Ib, Pu= 136 Ib 40 in. 60 in. 45°. -45° 60 in. V150 Ib
The rod has a diameter of 40 mm. (Figure 1) It is subjected to the force system F. F, = 920 N. 1350 N, F,= 540 N, Figure 1 of 1 100 mm 300mm B 100 N m
3:10 O submit this form. Not mtomol@cats.edu.ph? Switch account A member formed by connecting a steel bar into an aluminum bar. Assuming that the bars are prevented from buckling sideways, calculate the magnitude of force P that will cause the total length of the member to decrease by 0.25mm. The values for elastic modulus for steel and aluminum 2.1x10^5 Newton per millimeter squared and 7x10^4 Newton per millimeter squared respectively. 5 cm x 5 cm Šteel bar 30 cm t0 cm x 10 cm Aluminium bar 38 cm Your answer
Examine the rod below. It is fixed into a wall at the left hand end. From the wall to point B is 200mm. BC is 200mm long and CD is 200mm long. (Centreline to centreline distances). Point A lies on the positive Y-axis on a cross section halfway along BC. Three forces are applied at D. P=221.6, your individual load, is parallel to the z-axis. 400N is parallel to the y-axis and 200N is parallel to the x axis. The rod is a tube with an 80mm outer diameter and a wall thickness of 5mm. What is the net sigma (s) and the net tau (t) at Point A? Show all your working. Make sure you clearly indicate the direction/sign of each stress you calculate.
2. Three wires made of copper, zinc and aluminium are of equal lengths and have cross-sectional areas of 100, 150 and 200 square mm respectively. They are rigidly connected at their ends as shown in Fig. 4.16. If this compound member is subjected to a longitudinal pull of 220 kN, estimate the load carried on each wire. Take E = 130 GPa, E, = 100 GPa and E, = 80 GPa. [Ans. Pe= 65 kN, P, = 75 kN, P = 80 kN] 220 kN Fig. 4.16 Copper Ac-100 mm Zinc Az-D150 mm Aluminium A-200 mm
1. A frame is shown to the right. The link BC is t = 6mm thick (into the page) and has width, w (that is, the cross section of the link is t by w). The link is made of steel, with an ultimate strength of 450 MPa in tension. What is the required width of the link if the frame must support a load of P = 20 kN, with a factor of safety equal to 3. (Hint: BC is a two-force member.) Ans: w = 27.8 mm 600 mm. A 480mm 5 in.
A round steel bar with a diameter of 1.500 in is subjected to the axial loads shown. P1 = 95 k, P2 = 115 k, P3= 55 k, P4 = (P1-P2+P3) k. If Section 2 has a length, L2 = 65 inches, find the change in length of Section 2. Report the answer below in inches, absolute value, 3 significant digits. P1 Your Answer: 100 inches Round Steel Bar P2 Section 2 12 P3 80 inches P4
The assembly shown in Figure 5 consists of two sections of galvanized steel pipe connected using a reducing coupling at B. The smaller pipe AB has an inner diameter of d 16 mm and an outer diameter of do 18 mm, whereas the larger pipe BC has an inner diameter of d = 21 mm and an outer diameter of dae #24 mm. Take LAB= Lec 250 mm and G = 25 GPa. If the pipe is tightly secured to the wall at C. determine the angle of twist at point A A LAB 75 N 150 mm- 200 mm Lac 75 N 022