Refer to Figure 2. What is IB? 3.375mA Onone in the given choices O 4.4mA O 1.03125mA
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- How is a solid-state diode tested? Explain.For the Zener diode determine Vl and Iz. R1 1 3 1k2 V1 D1 R2 30V 1kHz 12V 1k2 0° Circuit F VL=Blank 1V Iz=Blank 2 mAUse Kirchhoff's law method Indicates the conduction status of the diode The result is the table of current and voltage values for each element Incorporates the diode conduction voltage if applicable 9) R1 200 Dzes; Rz 10, ojesi EI E2 E3
- Determine the voltage across the silicon diode assuming the complete diode model. Write the answer in terms of V and in four decimal places. r'd 10 ohms r'R = 100 Mohms R1 R2 13 5kQ 5kQ V1 D1 V2 20V 40V 0.Please find and draw the voltage over the load resistance, RL. Hint: 1N4148 is a Si-based diode. You have to show all the calculation details and verbal explanationsFind the current through the diode in the circuit shown. Assume the diode to be ideal. 50 92 www R₁ D V= 10 V = O 185 mA O 46 mA O 140 mA O 28 MA 592 wwww R₂ B
- Exercises: Determine VO and Ifor each circuit in figures. Assume that each of the diode in these circuits has a forward voltage drop of 0.7 V. V₁. D 1.1.2 D V. $5.140 1.V₁=V₁=OV. 2.V₁ =V₁=SV, and 3.V=OV & V, -5V. (d) C C ΣΙΩ T-15V D₂ +201 20 V₂ 14.02 I-15V 1. No pulses at either A or B. 2.A 30 V positive pulse at A or B, and 3. Positive pulses (30 V) at both A and B. (e)Find the current through the diode in the circuit shown. Assume the diode to be ideal. 50 92 www R₁ V = 10 V = D O 185 mA O 46 MA O 140 mA O 28 MA 50 R₂ BFind the current through the diode in the circuit shown. Assume the diode to be ideal. A 50 92 ww R₁ B V = 10 V 185 mA O 46 mA 140 mA 28 MA 592
- What is wrong in this diode? Mullimeter XMMI 35.733 M2 1 dB XMM1 IDEAL DIODE Set O A. Short Circuit O B. None of them O C. Nothing is wrong O D. Not enough data to answer this question O E. Open CircuitAssuming an ideal diode model for all the diodes in the circuit below, Calculate the voltage across and current flow through each diode 9kO 1N1199C R2 01 18kO IN1199C V2 12 V- R3 1kO D3 1N1199C R4 5kQAssuming ideal diode the voltage across the resistor R2 in the circuit shown in the Figure is: R1 E = +12V0- 2.2k2 RE1.8kN E, = +4V A 4.0 V 7.6 V 3.6 V D 4.4 V