r=0.60 Or-0.10 D Question 13 What is the value of SP for the following set of data? X 1 2 xy 8 1 9 Σx = 12 Σγ = 9 Exy = 21 SP-15
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- Exhibit 10-11 An insurance company selected samples of clients under 18 years of age and over 18 and recorded the number of accidents they had in the previous year. The results are shown below. Under Age 18 Over Age 18 N1 = 500 n2 = 600 Number of accidents = 180 Number of accidents = 150 We are interested in determining if the accident proportions differ between the two age groups. Refer to Exhibit 10-11. The value of the test statistic is .96 1.96 2.96 О 3.96Assume df = 13 and alpha = 0.05. If Pearson's r = 0.510, then the null _____ and the relationship between the variables is _____ . a. should be rejected; significant b. should be rejected; not significant c. should not be rejected; significant d. should not be rejected; not significantWhat is the relationship of alpha when OA moves to OB
- Illustration following data: Find out the regression coefficients of Y on X and X on Y from the Σ Χ= 50, X= 5, Σ Y= 60, Y-6, Σ ΧΥ- 350. Variance of X = 4, Variance of Y = 9.An 37. Calculate coeff. of Q.D. and Bowley's coeff. of skewness from the data given below: Profits (Rs. lakh) No. of Cos. Less than 10 20 20 30 40 40 50 50 56 60 59 (MBA., HFU., 2011) 70 60Question 1 of 10 A A. B only B. A only C. Neither aboons In 1924WINGS D. Both 0623) 00338 ded Which of the scatter plots above indicate a relationship between the two variables? 888 8
- Ref. No:. ct Kotli A.K Date:. A random Sample of 99 heads of houholds was taken from the customer list for state bank and frust Those Samples were asked to classify their own attitudes and their parents attitudes state towards borrowing money. the hypothesis that the repondents borrowing habits are inclopendant what they beleive their parents attitude to be. Let α=0.05 Also interpret the results Chi-Square Tests Parents Chi-Square 3.196 Likelhood Ratio 3.205 Nof valid Cases 95 3 cells (33.3%) have expected count Less than 5 1db. 4 14 Asymp- Sig (2-sided) 0.526 0.524. 3. 41°C 29 30 31 Why is it important to collect more than one set of data for each temperature? Why compute an average temperature?Where Alpha = 15