Questions 13 through 14 pertain to the situation described below: A 73.0-kg man is in an environment of –10.0°C. The temperature, area, and emissivity of his skin are 33.0°C, 1.73 m², and 0.820, respectively. Assume that his metabolic energy production is 211 J/s and his specific heat is 3.50 × 10³ J/(kg K). (13) What is the net emission power of his body? (A) 341 W; (B) 321 W; (C) 301 W; (D) 281 W; (E) 261 W. (14) What is the rate of his body temperature drop? (A) 2.39 °F/hr; (B) 2.59°F/hr; (C) 2.79°F/hr; (D) 2.99 °F/hr; (E) 3.19 °F/hr.

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter17: Energy In Thermal Processes: The First Law Of Thermodynamics
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Questions 13 through 14 pertain to the situation described below:
A 73.0-kg man is in an environment of –10.0°C. The temperature, area, and emissivity
of his skin are 33.0°C, 1.73 m², and 0.820, respectively. Assume that his metabolic energy
production is 211 J/s and his specific heat is 3.50 × 10³ J/(kg K).
(13) What is the net emission power of his body?
(A) 341 W; (B) 321 W; (C) 301 W; (D) 281 W; (E) 261 W.
(14) What is the rate of his body temperature drop?
(A) 2.39°F/hr; (B) 2.59°F/hr; (C) 2.79°F/hr; (D) 2.99°F/hr; (E) 3.19°F/hr.
Transcribed Image Text:Questions 13 through 14 pertain to the situation described below: A 73.0-kg man is in an environment of –10.0°C. The temperature, area, and emissivity of his skin are 33.0°C, 1.73 m², and 0.820, respectively. Assume that his metabolic energy production is 211 J/s and his specific heat is 3.50 × 10³ J/(kg K). (13) What is the net emission power of his body? (A) 341 W; (B) 321 W; (C) 301 W; (D) 281 W; (E) 261 W. (14) What is the rate of his body temperature drop? (A) 2.39°F/hr; (B) 2.59°F/hr; (C) 2.79°F/hr; (D) 2.99°F/hr; (E) 3.19°F/hr.
Expert Solution
Step 1

(13)

Given data

The mass of the man is m = 73 kg

The environment temperature is T = -10°C

The temperature of the skin is Ts = 33°C

The area of the skin is As = 1.73 m2

The emissivity of the skin is s = 0.820

The metabolic energy production is E = 211 J/s = 211 W

The specific heat is C = 3.50 x 103 J/kgK

 

The expression for the net emission power of the body is given as:

Ep=sAsTs4-T4

Substitute the value in the above equation.

Ep=0.82×1.73 m2×5.67×10-8 W/m2K4×306 K4-263 K4Ep=321 W

Thus, the net emission power emitted by the body is 321 W.

Thus, option (B) is correct.

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