Question 6 What are the possible count outcomes of this pseudo-code: Given count=6 Thread 1(...) Thread_2(...) { // do something // do something count++; count--; } } Just put the correct values in the value column for each step to indicate how you get each count value if each of count++ and count- can be executed in the following steps. Step Storage Value SO: Thread 1 execute register1 = counter register1 = S1: Thread 1 execute register1 = register1 + 1 register1 = S2: Thread 2 execute register2 = counter register2 = S3: Thread 2 execute register2 register2 -1 register2 = $4: Thread 1 execute counter = register1 counter = S5: Thread 2 execute counter register2 counter =

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question 6
What are the possible count outcomes of this pseudo-code:
Given count3D6
Thread_1(...)
{
// do something
Thread_2(...)
{
// do something
count++;
count--;
}
Just put the correct values in the value column for each step to indicate how you get each count value if each of count++ and count-- can be executed in the following steps.
Step
Storage
Value
SO: Thread 1 execute register1 = counter
register1 =
%3D
%D
S1: Thread 1 execute register1 = register1 +1
register1 =
%3D
%3D
register2 =
%3D
S2: Thread 2 execute register2 counter
register2 =
%3D
S3: Thread 2 execute register2 register2- 1
%3D
S4: Thread 1 execute counter = register1
counter =
counter=
%3D
S5: Thread 2 execute counter = register2
%3D
Transcribed Image Text:Question 6 What are the possible count outcomes of this pseudo-code: Given count3D6 Thread_1(...) { // do something Thread_2(...) { // do something count++; count--; } Just put the correct values in the value column for each step to indicate how you get each count value if each of count++ and count-- can be executed in the following steps. Step Storage Value SO: Thread 1 execute register1 = counter register1 = %3D %D S1: Thread 1 execute register1 = register1 +1 register1 = %3D %3D register2 = %3D S2: Thread 2 execute register2 counter register2 = %3D S3: Thread 2 execute register2 register2- 1 %3D S4: Thread 1 execute counter = register1 counter = counter= %3D S5: Thread 2 execute counter = register2 %3D
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