Question 1: Convert the following infix expression into postfix one: (A+B^D)/(D-F)+G PS: you have to illustrate the different steps of this conversion one by one. Token #Scan Postfix Expression Stack 1 2 3 4 15 6. 17 18 9 10 11 12 13 14 15 The final solution is: .... ... Question 2: Evaluate the postfix expression A B C D+ * / Where A = 66, B = 1, C = 12 and D=10 %3D
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- Solution Floating point representation: It is defined as the representation of floating numbers. It includes sign bit, exponent, and mantissa bits. Based on precision it has 2 types. 1. For IEEE 754 single-precision floating-point numbers, what is the exponent of a denormalized floating-point number in decimal? Solution: In IEEE 754 single-precision, exponent bits are 8. Therefore exponent = 2 ^(n-1) -1 = 2^(8-1) -1 = 127 OPTION D 2. For IEEE 754 single-precision floating-point numbers, how many bits for mantissa? Solution: In IEEE 754 single-precision, there are 23 bits for mantissa. sign = 1 bit exponent = 8 bits mantissa = 23 bits 3. For IEEE 754 single-precision floating-point numbers, which of the following is an example of NAN? Solution: In IEEE 754 single-precision, NAN is a special value where all exponents bits are 1's and the mantissa is non zero. a. 1 111 1 111 0000 0000 1101 0000 0000 0000 Exponent is not all 1's. Not a NAN b. 0 111 1 111 1000 0000…Problem Y: Implement the reader writer problem using pthreads and semaphores. You should allow multiple readers to read at the same time and only one single writer to write to the data set. You are required to use the following: 1. A semaphore rw_muter initialized to 1. 2. A semaphore muter initialized to 1. 3. An integer reader_count initialized to 0.A = {1,2,3} B = {1,2,3} C = {5,6,7} D = {0,1,2,3,4,5} Is A = C?
- C++ A robot is initially located at position (0; 0) in a grid [?5; 5] [?5; 5]. The robot can move randomly in any of the directions: up, down, left, right. The robot can only move one step at a time. For each move, print the direction of the move and the current position of the robot. If the robot makes a circle, which means it moves back to the original place, print "Back to the origin!" to the console and stop the program. If it reaches the boundary of the grid, print \Hit the boundary!" to the console and stop the program. A successful run of your code may look like:Down (0,-1)Down (0,-2)Up (0,-1)Left (-1,-1)Left (-2,-1)Up (-2,0)Left (-3,0)Left (-4,0)Left (-5,0)Hit the boundary! or Left (-1,0)Down (-1,-1)Right (0,-1)Up (0,0)Back to the origin! About: This program is to give you practice using the control ow, the random number generator, and output formatting. You may use <iomanip> to format your output. You may NOT use #include "stdafx.h".function result = result = ''; 1 tokens_to_str_code(token_mat, time_unit) 3 for i =1:size(token_mat,1) 4 5 if(token_mat (i,1) if(token_mat(i,2) > 4*time_unit) result = strcat(result,"-"); elseif((token_mat(i,2) > time_unit) && (token_mat(i,2) 8*time_unit) result = strcat(result,"/"); elseif((token_mat(i,2) 11 == 0) 12 13 14 4*time_unit) && (token_mat(i,2) < 8*time_unit)) 15 result strcat(result," "); %3D 16 end 17 end 18 end 19 end 20 21 Check Test Expected Got tokens %3D [1 4; е 3; 1 3; е 1; 1 3; е 1; 1 1; ө 1; 1 1 ]; time_unit = .5; disp( tokens_to_str_code( tokens, time_unit )) tokens = [ 0 4; 1 1457; 0 463; 1 1457; 0 463; 1 497; 0 1423; 1 1457; ---/..--.. --.---/..--.. о 463; 1 1457; 0 463; 1 1457; ө 3343; 1 497; ө 463; 1 497; 0 463; 1 1457; 0 1423; 1 1457; 0 463; 1 497; 0 463; 1 497; e 379 ]; time_unit = 240; disp( tokens_to_str_code( tokens, time_unit ))Computer Science A tool is attached to link 3 of the manipulator. This tool is described by TTW, the tool frame relative to the wrist frame. Also, a user has described his work area, the station frame relative to the base of the robot, as TSB. Write the subroutine Procedure SOLVE(VAR trels: frame; VAR current, near, far: vec3; VAR sol: boolean); where “trels” is the {T} frame specified relative to the {S} frame. Other parameters are exactly as in the INVKIN subroutine. The definitions of {T} and {S} should be globally defined variables or constants. SOLVE should use calls to TMULT, TINVERT, and INVKIN
- Write a program in c++ which should create a weighted graph of the values entered by the user andthen write functions that perform the following: 1. Depth first search of source and destination vertex2. Breadth first search of source and destination vertex3. Shortest path search of source and all destination vertices (Dijkstra’s algorithm)4. Shortest path search of source and destination vertex (Dijkstra’s algorithm) The program should present a menu of the options and should run until the user opts to quit.Regular expression to NFA to DFA conversion: Describes the process of taking a unique regular expression, converting that regular expression to an NFA, then converting the NFA into a DFA. Your regular expression must have at minimum two union, two concatenation, and two Kleene star operations. As followed, concatenations of single charaters can be condensed. Your regular expression cannot be a solved problem from any book. You should describe the regular expression with both processes to convert the regular expression to an NFA and the conversion of that NFA into a DFA.le.com/forms/d/e/1FAlpQLSc6PlhZGOLJ4LOHo5cCGEf9HDChfQ-tT1bES-BKgkKu44eEnw/formResponse The following iterative sequence is defined for the set of positive integers: Sn/2 3n +1 ifn is odd if n is even Un = Using the rule above and starting with 13, we generate the following sequence: 13 u13 = 40 u40 =20 u20 = 10→ u10 =5 u5 = 16 u16 = 8 ug = 4 → Us =2 u2 =1. It can be seen that this sequence (starting at 13 and finishing at 1) contains 10 terms. The below function takes as input an integer n and returns the number of terms generated by the sequence starting at n. function i-Seq (n) u=n; i=%3; while u =1 if statement 1 u=u/2; else statement 2 end i=i+1; end statement 1 and statement 2 should be replaced by: None of the choices statement 1 is "mod(u,2)=D%3D0" and statement 2 is "u = 3*u+1;" statement 1 is "u%2" and statement 2 is "u = 3*u+1;" O statement 1 is "mod(n,2)=30" and statement 2 is "u = 3*n+1;"
- C++ PROGRAMMINGTopic: HashTable - PolyHash Quadratic Explain the c++ code below.: SEE ATTACHED PHOTO FOR THE PROBLEM INSTRUCTIONS It doesn't have to be long, as long as you explain what the important parts of the code do. (The code is already implemented and correct, only the explanation needed). You can also explain line by line for an upvote, thanks. EXPLAIN THE CODE BELOW: #include <cstdlib> #include <math.h> #include <cstring> #include <iostream> using namespace std; class HashTable { string* table; int N; int count; // TODO: Polynomial Hash Code using a=7 int hash_code(string key) { int code; int hash = 0; for (int i = 0; i < key.size(); i++) { char ch = key[i]; code += ((ch - 96) * pow(7, key.size() - (i + 1))); } return code; } // TODO: This hash table uses a MAD compression function // where a = 11, b = 461, p = 919 int compress(int code) { return (((11*code)+461) % 919) % N; }…the Program in C++, Write a program that evaluates a valid postfix expression such as: 6 2 + 5 * 8 4 / -The program should read a postfix expression consisting of digits and operators into a string. Using modified versions of the stack functions implemented earlier in this chapter, the program should scan the expression and evaluate it. The algorithm is as follows: 1-While you have not reached the end of the string, read the expression from left to right. If the current character is a digit, Push its integer value onto the stack (the integer value of a digit character is its value in the computer’s character set minus the value of '0' in the computer’s character set). Otherwise, if the current character is an operator, Pop the two top elements of the stack into variables x and y. Calculate y operator x. Push the result of the calculation onto the stack. 2-When you reach the end of the string, pop the top value of the stack. This is the result of the postfix expression. [Note: In Step…import java.lang.System; 3. public class FibonacciComparison { 4. // Fibonacci Sequence: 0, 1, 1, 2, 3, 5, 8 .... /* 7 input cases 8. 1) 0 9 2) 3 10 3) -1 11 4) 9 12 output cases 13 1) 0 14 2) 2 15 3) 0 16 4) 34 17 */ // Note that you need to return 0 if the input is negative. // Please pay close attention to the fact that the first index in our fib sequence is 0. 18 19 20 // Recursive Fibonacci public static int fib(int n) { // Code this func. 21 22 23 24 return -1; 25 26 // Iterative Fibonacci 27 28 public static int fiblinear(int n) { // Code this func. 29 30 return -1; 31 32 33 public static void main(String[] args) { 34 // list of fibonacci sequence numbers int[] nlist w { 5,10, 15, 20, 25, 30, 35, 40, 45}; 35 36 37 // Two arrays (one for fibLinear, other for fibRecursive) to store time for each run. // There are a total of nlist.length inputs that we will test double[] timingsEF = new double[nlist.Length]; double[] timingsLF = new double[nlist.length]; 38 39 40 41 42 // Every…