Ql- The following data relates to the office air conditioning plant having maximum seating capacity of 25 occupants: Outside design conditions Inside design conditions Solar heat gain Latent heat gain per occupant = 120 W Sensible heat gain per occupant = 100 W Lightening load Sensible heat load from other sources = = 34°C DBT, 28C WBT = 24°C DBT, 50% RH = 9120 W = 2500 W 11000 W Infiltration load = 16 m / min CADD
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- A summer air-conditioning shown below is required to maintain a certain room at specified conditions. The layout of the system is indicated on the next page and the specifications are listed below.System specifications:Required room temperature: 23⁰C, 50% Relative humidityAtmospheric pressure: 101 kPaOutside air conditions: 30⁰C, 80% Relative humiditySensible heat gain: 5 kWLatent heat gain: 4 kWTemperature rise across fan: 1.5⁰CTemperature of air leaving cooler: 12⁰CTemperature of air entering room: 18⁰CApparatus dew point of cooler: 7⁰C Draw the processes on a psychrometric chart and determine the following: 1.The ratio of mass flow rate of re-circulated air to the mass flow rate of air supplied to the room. 2.The heat removed by the cooling coil.3.The heat supplied in the re-heating coil. 4.The cooling coil bypass factor.Q1- The following data relates to the office air conditioning plant having maximum seating capacity of 25 occupants: Outside design conditions Inside design conditions Solar heat gain Latent heat gain per occupant = 120 W Sensible heat gain per occupant = 100 W Lightening load Sensible heat load from other sources = 11000 W = 34°C DBT, 28°C WBT = 24°C DBT, 50% RH = 9120 W = 2500 W Infiltration load = 16 m / mim tas(ADP) = 8 °C Assuming 30% fresh air and 70% of recirculated air passing through the evaporator coil and the by-pass factor of 0.15, find the dew point temperature of the coil, capacity of the plant, Volume flow rate of supply air, Supply air temperature.A summer air-conditioning shown below is required to maintain a certain room at specified conditions. The layout of the system is indicated on the next page and the specifications are listed below.System specifications:Required room temperature: 23⁰C, 50% Relative humidityAtmospheric pressure: 101 kPaOutside air conditions: 30⁰C, 80% Relative humidity Sensible heat gain: 5 kWLatent heat gain: 4 kWTemperature rise across fan: 1.5⁰CTemperature of air leaving cooler: 12⁰CTemperature of air entering room: 18⁰CApparatus dew point of cooler: 7⁰C
- Example 2: The following data apply to an air-conditioning system RSH=11.6 kW RLH=11.6 Kw In side condition 25°C & RH=50% & outside condition 35°C DBT & 27.8°C WBT Return air from the room is mixed with the outside air before entering the cooling coil a ratio 4:1 Return air from the room is mixed with the air leaving the cooling coil at a ratio 1:4, cooling coil by pass factor =0.1. The air may be reheated if necessary before suppling the condition, assume tdp=10°C. find 1- Supply air condition to the room 2- Refrigeration load (Colling coil load) 3- Total refrigeration capacity d- The quantity of fresh air suppliedHello Sir,Good Morning.I have a question in my homework related thermodynamics lesson. The following below is my question. Please advice. Thank you. Regards,Irfan An air conditioning system is used to keep the house at 65°F when the outside temperature is 85°F. The house gets heat through the walls and windows at a rate of 810 Btu/min, and the rate of heat generation inside the house from occupants, lights, and equipment is 120 Btu/min. Determine the minimum power input required for this air conditioning system.In an absorption refrigerator, the energy driving the process is sllPplied not as work, but as heat from a gas flame. (Such refrigerators commonly use propane as fuel, and are used in locations where electricity is unavailable. *) Let us define the following symbols, all taken to be positive by definition: Qf = heat input from flame Qe = heat extracted from inside refrigerator Qr = waste heat expelled to room Tf = temperature of flame Te temperature inside refrigerator Tr = room temperature Use the second law of thermodynamics to derive an upper limit on the COP, in terms of the temperatures Tf, Te, and Tr alone.
- In an absorption refrigerator, the energy driving the process is sllPplied not as work, but as heat from a gas flame. (Such refrigerators commonly use propane as fuel, and are used in locations where electricity is unavailable. *) Let us define the following symbols, all taken to be positive by definition: Qf = heat input from flame Qe = heat extracted from inside refrigerator Qr = waste heat expelled to room Tf = temperature of flame Te temperature inside refrigerator Tr = room temperature Explain why the "coefficient of performance" (COP) for an absorption refrigerator should be defined as Qc/Qf.QUESTION 1 A 120-ton capacity chiller, based on a refrigeration cycle, is used to maintain a coolant temperature of 35 deg. F. The chiller exchanges heat to the surrounding air at 70 deg. F. This unit utilizes a 150 hp motor. What is the rate of heat removal from the coolant, in Btu/hr? O1,440,000 O 381,675 O 1,821,675 O 120 QUESTION 2 A powerplant operates between a furnace at 990 deg. Fand cooling water delivered from a nearby river at 70 deg. F. What is the maximum possible efficiency of this powerplant, in %? Oa. 72.8% Ob. 27.2% Oc 92.9% Od.63.4% QUESTION 3 If fuel oil is supplied to a power plant furnace at a rate of 60,000 gallons/hr, and the oil has a heating value of 150,000 Btu/gallon, and the plant has a thermal efficiency of 30%, what is the power output of this plant (in MW)? Oa. 2637.6 Ob.9000 Oc 2700 d. 791.311. Five large hotels in Miami, USA, use their own air-conditioning units, which have a c.o.p. 3.1. It is proposed that the cooling systems of the five hotels be substituted with a larger, modern unit that would have a c.o.p. 3.7. The total installed capacity of the five hotels is 2,600 tons of air-conditioning and the current systems are in use for 3,200 hours every year. Determine: a) the annual energy savings from this substitution and b) the annual avoidance of CO₂ emissions if, currently, 72% of the electric energy in the Miami area is obtained from coal power plants and 28% from nuclear power plants.
- 01. A refrigerant 22 system having a refrigerating capacity of 55 kW operates with an evaporating temperature of 5°C and rejects heat to water cooled condenser. The compressor is hermetically sealed. The condenser has a U value of 450 W/m².K and a heat-transfer area of 18 m? and receives a flow rate of cooling water of 3.2 kg/s at a temperature of 30°C. What is the condensing temperature?A- Specify is the following conditions are comfort or not: 1- DBT 22 C° and WBT = 16 Cº 2- DBT=24 C° and RH= 80 % B- Compare between the following: 1- Cooling load and the heat gain. 2- Overall heat transfer coefficient and convection heat transfer coefficient.3:57 A Done lecture 7_b5ee35c08478147bb8a3744a... Lec. (7) tar -Dry bulb temperature O Example (1): An air conditioning equipment (figure) have the following: - Supply air mass-1.26 kg/s. The cooling coil receives 20 % outdoor air and 80% return air. tdz Fig. 18.14. Representation of supply air condition and room design condition. 0.252 kg/s Refrigeration and A/C - Outdoor air conditions are: 28°C db, 19.5°C wb Return air conditions are: 22°C db, 50% RH. The mixture air condition outlet the cooling coil are: 10°C db, 0.00735 kg/kgda Draw the system on the Psychrometric chart, then calculate: 1. Cooling coil load. 2. Room sensible heat. 3. Room latent heat. 4. Fresh (outdoor) load. 5. Duct and fan heat gain 6. Sensible heat ratio SHR. If the supply air temperature increases with a value 1°K due to fan motor heat gain and 2°K due to duct heat gain. . ← 1.008 kg/s R to Dr. Omar M. Ali LTE الغرفة المراد تكييفها (22,50 %) 1.26 kg/s R Grand Sensible Heat Factor It is defined as the ratio of…