Q3\ To design the combinational circuit by using a decoder and external gates in the design defined by the following two Boolean functions: - F₁ A B + AC + ABC F₂ AB +ABC + AC O Option 1 1. Choose the group numbers for each function (F) of the following:- F1= F2= A B 0 cor 3x8 decoder Option 3 3x3 1 2. choose the correct block diagram which satisfies the design * Option 2 O 2 3 4 A- B 5 3x8 decader Option 1 6 7
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- Part 4: The data-input and data-select waveforms in Figure 7 are applied to the multiplexer. Determine the output waveform F in relation to the inputs. DO D1 D2 D3 1. so s1 Figure_7USE DIGITAL LOGIC AND DESIGN Part 1: In Figure_4; we have 4-bit Comparator using 2-bit Comparators block. You have to satisfy given condition by applying all data on figure 4. At the end, given condition should produce HIGH output and other two should be LOW. A3 A2 A1 A0 = 1101 and B3 B2 B1 B0 = 1110 Figure_4 Part 2: The serial data-input waveform (Data in) and data-select inputs (S0 and S1) are shown in Figure_5. Determine the data-output waveforms from D0 through D3. Figure_5 Part 3: Decoder can be useful when we have to decode some specific numbers from their equivalent code. Figure 6 has a concept of 3 to 8 line decoder from which you have to generate output waveform from D0 to D7 with proper relationship to input. Figure_6 Part 4: The data-input and…Q/ What does this mean in an electrical singlevline diagram? TEST BLOCK 1 C11A C13 14 *13 C72 16 15 C31 C31A C33 18 17 C74 20 19 CT1-3 800/5A P1s1 CLASS SP20 25VA P2152 C51 C51A C53 22 21 C70 C78 24 23 STUD TYPE CT SHORTING TERMINALS AELI FT-14 即 帕
- Design a code converter that converts a decimal digit from BCD to excess-3 code, the input variables are organized as (A B C D) respectively with A is the MSB, the output variables are organized as (W XY Z) respectively with W is the MSB, put the invalid decimal numbers as don't care. W=A+BD+BC' W=A+BD+BC, W=A'+BD+BC W= BC'D'+B'D+B'CDesign a code converter that converts a decimal digit from BCD to excess-3 code, the input variables are organized as (A BC D) respectively with A is the MSB, the output variables are organized as (W XY Z) respectively with W is the MSB, put the invalid decimal numbers as don't care. X= BCD'+B'D+B'C X= BC'D'+B'D+BC X= BC'D'+B'D+B'C X= BC'D'+BD+B'CMoving to the next question prevents changes to this answer. Question 2 What are the two most common methods of PLD design entry? logic simulator and AND gates O logic simulator and design entry design entry and schematic entry O schematic entry and AND gates
- Simplify the following SOP and POS: a) A'B+A'BC+A'C' b) (A+C)(A+B')(A+B'+C')(A+B+D')Design a code converter that converts a decimal digit from BCD to excess-3 code, the input variables are organized as (A BC D) respectively with A is the MSB, the output variables are organized as (W X Y Z) respectively with W is the MSB, put the invalid decimal numbers as don't care. X= BCD'+B'D+B'C X= BC'D'+B'D+BC X= BC'D'+B'D+B'C X= BC'D'+BD+B'C5. Assume d3d₂d₁do is a BCD number and derive Boolean expression for segments b,c,e,f,g in a seven segment display in terms of d3d₂d₁do g 4 d Based on your boolean expressions derive the values of b,c,e,f,g segments when i. d3d₂d₁do= (0100) 2 ii. d3d₂d₁do = (0111)₂ iii. d3d2d₁do (1000)2
- I need to implement the 1-4 with 1-bit demultiplexer in a diagram. How to draw it. and how to do the final equationUsing any design approach, plan and design the following problem: (show the Block Diagram, Truth Table, Simplification Approach Solution, Circuit Diagram) 2. Simple Security System A simple security system for two doors consists of a card reader and a keypad. Cand Reader To Door To Dor 2 To Alam Logic Circuit D E Keypad A person may open a particular door if he or she has a card containing the corresponding code and enters an authorized keypad code for that card. The outputs from the card reader are as follows: A B No card inserted Valid code for door 1 0 1 0 0 Valid code for door 2 1 1 Invalid card code 10 To unlock a door, a person must hold down the proper keys on the keypad and, then, insert the card in the reader. The authorized keypad codes for door 1 are 101 and 110, and the authorized keypad codes for door 2 are 101 and 011. If the card has an invalid code or if the wrong keypad code is entered, the alarm will ring when the card is inserted. If the correct keypad code is…What will be the final value of DI after executing the following piece of code? Execute the instructions dependently one after another. CLD MOU CX,OFOH MOU AX,05678H MOU DI,01000H MOU ES, DI SUB DI, DI REPNZ SCASB -R AX-0000 DS-073F 073F:0100 0000 D 1000:0 F 1000:0000 92 00 14 12 54 56 44 78-AD 56 78 FO 00 00 00 00 BX-0000 CX-0000 DX-0000 SP-00FD ES-1000 SS%3073F CS=073F BP-0000 SI=0000 DI=0000 IP-0100 NU UP EI PL NZ NA PO NC ADD IBX SI1,AL DS:0000 CD TUDX.Ux..... .... Notes: 1- Use the DEBUG window to answer this question (values shown are prior to execution and in hexadecimal 2- Write down the final value of DI as four hexadecimal digits without any additional characters.