(Q3) Let X₁ equal the fill weight in June and X2 the fill weight in October for an 8 kilogram box of industrial bleach. Test the hypothesis Ho 12 vs H₁: μμ given that ni = 90 observations of X₁ yielded 1 observations of X2 yielded 2 = 8.07, 82 = 0.054. = 8.10, 81 0.117 and n₂ = 110 (i) What is your conclusion if α = 0.05? (ii) What is the approximate p-value of this test?
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- you are testing ho: u=0 against ha=u not equal 0 based on an SRS of four observations from a normal population. what are the values of the t static are statistically signification at a=0.005 levels? (a) t>7.453 (b) t<-7.453 or t>7.453 (c) t<-5.598 or t >5.598Jitter is a term used to describe the variation in conduction time of a water power system. Low throughput jitter is eritical to successful waterline technology. An investigation of throughput jitter in the opening switch of a prototype system yielded the following descriptive statistics on conduction time for 18 trials: =334.8 nanoseconds and s = 6.3 nanoseconds. (Conduction time is defined as the length of time required for the downstream current to equal 10% of the upstream current.) a) Construct a 95% confidence interval for the true standard deviation of conduction times of the prototype system. b) A system is considered to have low throughput jitter if the true standard deviation of conduction times is less than 7 nanoseconds. Does the prototype system satisfy this requirement? Use a = 0.01.Let's examine the levels of levels of sodium in the blood. 20 people yield the following results (in mEq/L): y = 131.95 s = 2.544 (a) Test H0: μ = 135 using α = 0.001 (that's not a typo) (b) Figure out the p-value. (c) What is the smallest value of α for which you would reject the H0? (c) For which of the following values of α would you reject? i) .10 ii) .05 iii) .01 iv) .001 v) .00000001
- An experiment to compare the tension bond strength of polymer latex modified mortar (Portland cement mortar to which polymer latex emulsions have been added during mixing) to that of unmodified mortar resulted in x = 18.11 kgf/cm² for the modified mortar (m = 42) and y = 16.82 kgf/cm² for the unmodified mortar (n = 32). Let μ₁ and μ₂ be the true average tension bond strengths for the modified and unmodified mortars, respectively. Assume that the bond strength distributions are both normal. (a) Assuming that 0₁ = 1.6 and ₂ = 1.3, test Ho: ₁ - ₂ = 0 versus H₂: M₁-M₂ > 0 at level 0.01. Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. O Reject Ho. The data does not suggest that the difference in average tension bond strengths exceeds 0. O Fail to reject Ho. The data suggests that the difference in average tension bond strengths exceeds…An experiment to compare the tension bond strength of polymer latex modified mortar (Portland cement mortar to which polymer latex emulsions have been added during mixing) to that of unmodified mortar resulted in x = 18.11 kgf/cm² for the modified mortar (m = 42) and y = 16.82 kgf/cm² for the unmodified mortar (n = 30). Let μ₁ and μ₂ be the true average tension bond strengths for the modified and unmodified mortars, respectively. Assume that the bond strength distributions are both normal. (a) Assuming that ₁ = 1.6 and ₂ = 1.3, test Ho: ₁ - ₂ = 0 versus H₂ : ₁ - ₂ > 0 at level 0.01. Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. O Reject Ho. The data does not suggest that the difference in average tension bond strengths exceeds 0. O Fail to reject Ho. The data does not suggest that the difference in average tension bond strengths…An experiment to compare the tension bond strength of polymer latex modified mortar (Portland cement mortar to which polymer latex emulsions have been added during mixing) to that of unmodified mortar resulted in x = 18.18 kgf/cm² for the modified mortar (m = 42) and y = 16.85 kgf/cm² for the unmodified mortar (n = 32). Let μ₁ and ₂ be the true average tension bond strengths for the modified and unmodified mortars, respectively. Assume that the bond strength distributions are both normal. (a) Assuming that 0₁ = 1.6 and ₂ = 1.3, test Ho: M₁ M₂ = 0 versus Ha: M₁ M₂ > 0 at level 0.01. 1 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = 4.74 X P-value = State the conclusion in the problem context. Ⓒ Reject Ho. The data suggests that the difference in average tension bond strengths exceeds 0. O Reject Ho. The data does not suggest that the difference in average tension bond strengths exceeds…
- An experiment to compare the tension bond strength of polymer latex modified mortar (Portland cement mortar to which polymer latex emulsions have been added during mixing) to that of unmodified mortar resulted in x = 18.17 kgf/cm² for the modified mortar (m = 42) and y = 16.82 kgf/cm² for the unmodified mortar (n = 31). Let μ₁ and ₂ be the true average tension bond strengths for the modified and unmodified mortars, respectively. Assume that the bond strength distributions are both normal. (a) Assuming that 0₁ = 1.6 and 0₂ = 1.3, test Ho: M₁ M₂ = 0 versus Ha: M₁ - H₂> 0 at level 0.01. Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) Z P-value = (b) Compute the probability of a type Il error for the test of part (a) when µ₁ - H₂ = 1. (Round your answer to four decimal places.) (c) Suppose the investigator decided to use a level 0.05 test and wished B = 0.10 when M₁ M₂ = 1. If m = 42, what…An engineer in charge of a production process that produces a stain for outdoor decks has designed a study to test the research hypotheses that an additive to the stain will produce an increase in the ability of the stain to resist water absorption. The mean absorption rate of the stain without the additive is 40 units. The engineer places that stain with the additive on n=50 pieces of decking material and records y- = 36.5 and s = 13.1. Let u denote the mean absorption rate of the stain. You must state the null and the alternative hypotheses.The result below gives the amount (mg/mL) of ephedrine hydrochloride found in pharmaceutical preparations of Ephedrine Elixir B.P. by two different methods: derivative ultraviolet spectroscopy and an official assay method (the nominal amount in each sample was 3 mg/mL). Test whether the results obtained by the two methods differ significantly.
- I want to assess whether or not students produce more stress hormones (cortisol) after watching different types of movies. I collect saliva samples (to assess cortisol, stress) from students after they watch an action movie and then another (two days later) after they watch a horror movie. The amount of stress hormone in the saliva is measured as ng/mL.Test the hypothesis that saliva cortisol levels will be different between the two genres of movies at an alpha of 0.05. (Have action - horror be set for your differences). Data: Action Movie Horror Movie 10 12 -2 15 18 -3 16 17 -1 20 21 -1 24 22 2 24 23 1 26 27 1 13 16 -3 18 20 -2 19 23 -4 20 15 5 24 25 1 What is the obtained t value? What conclusion do you draw?I want to assess whether or not students produce more stress hormones (cortisol) after watching different types of movies. I collect saliva samples (to assess cortisol, stress) from students after they watch an action movie and then another (two days later) after they watch a horror movie. The amount of stress hormone in the saliva is measured as ng/mL.Test the hypothesis that saliva cortisol levels will be different between the two genres of movies at an alpha of 0.05. (Have action - horror be set for your differences). a. What is the null hypothesis? b. What is the alternative hypothesis? Complete the Chart: (Differences between the two) Action Movie Horror Movie 10 12 15 18 16 17 20 21 24 22 24 23 26 27 13 16 18 20 19 23 20 15 24 25I want to assess whether or not students produce more stress hormones (cortisol) after watching different types of movies. I collect saliva samples (to assess cortisol, stress) from students after they watch an action movie and then another (two days later) after they watch a horror movie. The amount of stress hormone in the saliva is measured as ng/mL.Test the hypothesis that saliva cortisol levels will be different between the two genres of movies at an alpha of 0.05. (Have action - horror be set for your differences). a. What is the null hypothesis? b. What is the alternative hypothesis? Data: Action Movie Horror Movie 10 12 15 18 16 17 20 21 24 22 24 23 26 27 13 16 18 20 19 23 20 15 24 25