Problem 4.6: Determine the charge of the nucleus in a Rutherford Scattering Experiment b = +30 Set value and play: one alpha angle= +17.584 Kinetic energy = 9 30 MeV | impact parameter = fm (10-15 m) The animation shows one alpha particle impacting a nucleus. You can change both the incident angle and the impact parameter. What is the charge on the nucleus? Restart. End of Animation

An a grain with a kinetic energy of 5 MeV approaches an Au (gold) nucleus with the sighting parameter equal to the radius of the Au nucleus. a. Find the maximum approach distance of the a particle to the nucleus in these conditions. (Za=2, ZAu=79 and rAu=7 fm) b. How close can the alpha particle get to the gold core? c. Únder what conditions can this approach take place (Assume the target core does not rebound)

Radius of an atomic nucleus is of the order 2.5 fm. What is the minimum energy that an electron should have to be found inside the atomic nucleus? Is this possible in reality? Explain. Provide the final answer below and upload the solution in the MCr-

Question 3 The nuclear radii of aluminum and gold are approximately r = 3.6 fm and 7.0 fm, respectively. The radii of protons and alpha particles are 1.3 fm and 2.6 fm, respectively. In both (a) and (b), perform the calculation for aluminum and for gold. a) What energy a particles would be needed in head-on collisions for the nuclear surfaces to just touch? (This is about where the nuclear force becomes effective.) Answer b) What energy protons would be needed? Answer

Text a Vorkbook t Sharing ings Item 9 Part A How many protons and how many neutrons are in 2H? Enter your answers numerically separated by a comma. Z, N = 2,1 Submit Part B VE ΑΣΦ X Incorrect; Try Again; 4 attempts remaining Z, N= Previous Answers Request Answer How many protons and how many neutrons are in 32P ? Enter your answers numerically separated by a comma. Submit VE ΑΣΦΑ Request Answer f t O ? ?

A beta ray is incident normally on a 0.35 cm thick lead slab (density = 11.4 g/cm³) lies on the top of Lucite slab (density = 1.19 g/cm). The beta rays emerge from the lead slab with an energy T1=3.69 MeV. The range R (in g/cm2) of the electrons is related to the kinetic energy T (in MeV) by the following: Lucite: R=0.334T1.5 Lead: R=0.426T T Lead 0.35 cm T1 d. Lucite What minimum thickness of Lucite (in cm) needed to stop the beta rays from Choose... + emergina the slah?

Consider the lead isotope 207Pb.a. How many electrons, protons, and neutrons are in a neutral 207Pb atom?b. The lead nucleus has a diameter of 14.2 fm. What is the density of matter in a lead nucleus?c. The density of lead is 11,400 kg/m3. How many times the density of lead is your answer to part b?

SA1. Consider two different alpha-particle scattering experiments, one in which the particle is deflected by 45° and another in which it is deflected from the same target by 135°. In the 45° scattering experiment, is the maximum force experienced by the alpha particle greater than, less than, or the same as the maximum force experienced by the alpha particle in the 135° scattering experiment? EXPLAIN YOUR ANSWER.

1 For the Rutherford (Geiger and Marsden) experiment with 5.5 MeV alpha particles on a 1 um gold foil, and for the six angles (decades) between 10-5 and 10° rad, calculate the Rutherford differential cross section (DCS), dor/d2, (a) without and (b) with screening. Represent both results graphically and draw conclusions. Answer: The nonscreened DCS values vary between 1.7137x10-3 and 2.0273×10 23 cm? rad-' in the interval [10-5-1 rad]. The screening angle is 3.7 x 10-3 rad, and the corresponding screened DCS values vary between 9.3620 x 10-14 and 2.0273 x 10-23 cm² rad-'. The screening Xa cuts off the otherwise increasing DCS with decreasing angle, which remains practically constant below X

Question no.1 Assuming nucleus to be uniformly charged, calculate the work done against electrostatic forces in giving it a charge Ze. (Subject:Nuclear Physics).