Problem 16.027 - Voltage across capacitorFind (t) for t> 0 in the given circuit. Assume /= 8u(t) A.t=01 Hm4.5 A10 92+v=4F 5ΩIThe value of v(t) = [A + (B)eCt+ (D)e-4.949tju(t) Vwhere A = 1667 X B = -1683.630 X = 0.07576 X and D = 16.680X

Answered: Image /qna-images/answer/89ba09d6-7dba-4ef1-90ab-7bdc5b89cb15.jpg

Problem 16.027 - Voltage across capacitor Find (t) for t> 0 in the given circuit. Assume /= 8u(t) A. t=0 1 H m 4.5 A 10 Ω www + v=4F 592 - The value of (t)=[A + (B)eCt. where A = 1667 , B = -1683.630 www +(D)e-4.949t Ju(t) V C= = 0.07576 X " and D = 16.680

Problem 16.027 - Voltage across capacitor Find (t) for t> 0 in the given circuit. Assume /= 8u(t) A. t=0 1 H m 4.5 A 10 Ω www + v=4F 592 - The value of (t)=[A + (B)eCt. where A = 1667 , B = -1683.630 www +(D)e-4.949t Ju(t) V C= = 0.07576 X " and D = 16.680

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Question

Problem 16.027 - Voltage across capacitor
Find (t) for t> 0 in the given circuit. Assume /= 8u(t) A.
t=0
1 H
m
4.5 A
10 92
+
v=4F 5Ω
I
The value of v(t) = [A + (B)e
Ct+ (D)e-4.949tju(t) V
where A = 1667 X B = -1683.630 X = 0.07576 X and D = 16.680
X

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Step 1: Node 1 and node 2 voltage

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Step 2: Voltage across the capacitor is same as node 1

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