Problem 1 Please choose the correct answer and also write down your solution. (1) The section supports an upward internal shear force and a ciockwise intern absolute maximum shear stress occur? a. Point A b. Point B c. Point C d. Point D (2) The internal force and moment of the section have been determined as = 100i + 300k (N) and M = 50i + 40j (N - m). Where does the absolute maximum normal stress occur? a. Point A b. Point B

Problem 1 Please choose the correct answer and also write down your solution. (1) The section supports an upward internal shear force and a ciockwise intern absolute maximum shear stress occur? a. Point A b. Point B c. Point C d. Point D (2) The internal force and moment of the section have been determined as = 100i + 300k (N) and M = 50i + 40j (N - m). Where does the absolute maximum normal stress occur? a. Point A b. Point B

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Determine the resultant internal loadings acting on the cross section at B of the pipe shown. End A is subjected to a vertical force P and a horizontal force Q. Use P = 90 N and Q = 70 N. a. Determine the internal axial force (in N) in section B. b. Determine the internal shear force (in N) in section B. c. Determine the internal torque (in N-m) in section B. With FBD please thank you.
Below Figure shows the section of an angle purlin. A bending moment of 60 5 kN.m is applied to the purlin in a plane at an angle of 30 deg to the vertical y axis. If the sense of the bending moment is such that both its components Mx and My produce tension in the positive xy quadrant, calculate the maximum direct stress in the purlin, stating clearly the point at which it acts. * 100 mm BỊ 10mm 30° C ID 10mm 57 MPa. 89 MPa. Non Above 72 MPa. 125mm
1. A circular shaft with a keyway can be approximated by the section shown in Fig. r=b Ay r r=2acose Figure 1: Circular shaft with a keyway. The keyway is represented by the boundary equation r = b and the shaft is represented by the boundary equation r = 2a cos 0. Show that using a Prandtl stress function of the form ²) (₁ (1-2a cos) X v = K (b² − ²) (1 – : will solve the problem of torsion on this shaft and find the constant K (assume an applied torque T). Compute the shear stress components Txz and Tyz. (Hint: start by converting the stress function to Cartesian coordinates).
Question 2)  arm of Figure  B  from point x z  plane, a horizontal angle of θ = 44 ° angled F = 26 kN size and a force  C  at the point   z  in the direction of M = 18 kn.m acts a moment in size.   The lengths of the arm are also given as  L 1 = 1.6 m  and  L 2 = 1.3 m  . It is desired to determine the stress state of point A on the aa section taken from the arm. The radius r of the section  is  r=0.029 m  and the shear modulus of the sleeve material is also G = 79 Gpa . According to this; Question 2-C) Find the normal stress caused by the normal force   at point A  (  Write your result in  MPa .) Question 2-D) Find the normal stress  caused by the bending moment   at point A. (Your result  MPa  in the size of  your font.)
Question 2)  arm of Figure  B  from point x z  plane, a horizontal angle of θ = 44 ° angled F = 26 kN size and a force  C  at the point   z  in the direction of M = 18 kn.m acts a moment in size.   The lengths of the arm are also given as  L 1 = 1.6 m  and  L 2 = 1.3 m  . It is desired to determine the stress state of point A on the aa section taken from the arm. The radius r of the section  is  r=0.029 m  and the shear modulus of the sleeve material is also G = 79 Gpa . According to this; Question 2-A)     Find the shear stress at point A due to the  shear force . (  Write your result in  MPa .) Question 2-B)  Find the shear stress due   to the torsional moment at point A. (  Write your result in  MPa .) Question 2-C) Find the normal stress caused by the normal force   at point A  (  Write your result in  MPa .) Question 2-D) Find the normal stress  caused by the bending moment   at point A. (Your result  MPa  in the size of  your font.)
Question 2)  arm of Figure  B  from point x z  plane, a horizontal angle of θ = 44 ° angled F = 26 kN size and a force  C  at the point   z  in the direction of M = 18 kn.m acts a moment in size.   The lengths of the arm are also given as  L 1 = 1.6 m  and  L 2 = 1.3 m  . It is desired to determine the stress state of point A on the aa section taken from the arm. The radius r of the section  is  r=0.029 m  and the shear modulus of the sleeve material is also G = 79 Gpa . According to this; Question 2-A)     Find the shear stress at point A due to the  shear force . (  Write your result in  MPa .) Question 2-B)  Find the shear stress due   to the torsional moment at point A. (  Write your result in  MPa .) Question 2-C) Find the normal stress caused by the normal force   at point A  (  Write your result in  MPa .)
3. Four pulleys are attached to the 50-mm-diameter aluminum shaft. If torques are applied to the pulleys as shown in the figure, determine the maximum shear stress in each segment and the angle of rotation of pulley D relative to pulley A. Use G = 28 GPa for aluminum. a. Tab= b. Tbc= C. Tbc= ad= 1100 N·m 800 N·m D C 900 N·m 600 N m B A 2 m3 m2 m
1) Determine the normal force at point E Express your answer to three significant figures and include the appropriate units. 2) Determine the shear force at point E. Express your answer to three significant figures and include the appropriate units. 3) Determine the moment at point E. Express your answer to three significant figures and include the appropriate units.
Question 4: Two wrenches are used to tighten the pipe. If the pipe is made from a material having an allowable shear stress of Tallow = 85 MPa, check the allowable force for external and internal diameter of pipe and determine the allowable maximum force P that can be applied to each wrench. The pipe has an outer diameter of 25 mm and inner diameter of 20 mm. 250 mm B 250 mm Figure 4 Answer: Torque = 0.5P, Polar moment of inertial J = 2.26 x 108 m4, outer diameter PS %3D 307.36N, inner diameter P S 384.2 N, Pallowable = 307.36N
Question 2) arm of Figure B from point x z plane, a horizontal angle of θ = 38 ° angled F = 29 kN force sized and C from the point z direction M = 17 kn.m acts a moment in size. The lengths of the arm are also given as L 1 = 1.5 m and L 2 = 1.1 m . It is desired to determine the stress state of point A on the aa section taken from the arm. The radius r of the section is r=0.015 m and the shear modulus of the arm material is also G = 78 Gpa . According to this; Question 2-C) Find the normal stress caused by the normal force at point A ( Write your result in MPa .) Question 2-D) Find the normal stress caused by the bending moment at point A. (Your result MPa in the size of your font.)
Question 2) arm of Figure B from point x z plane, a horizontal angle of θ = 38 ° angled F = 29 kN force sized and C from the point z direction M = 17 kn.m acts a moment in size. The lengths of the arm are also given as L 1 = 1.5 m and L 2 = 1.1 m . It is desired to determine the stress state of point A on the aa section taken from the arm. The radius r of the section is r=0.015 m and the shear modulus of the arm material is also G = 78 Gpa . According to this; Question 2-A) Find the shear stress at point A due to the shear force . ( Write your result in MPa .) Question 2-B) Find the shear stress due to the torsional moment at point A. ( Write your result in MPa .) Question 2-C) Find the normal stress caused by the normal force at point A ( Write your result in MPa .)
Answer p1 and Part 2: Determine the shear force acting at each of the following locations:(a) x = 11.0- ft (i.e., just to the left of point B)(b) x = 11.0+ ft (i.e., just to the right of point B)(c) x = 28.5 ftNote that x = 0 at support A. When entering your answers, use the shear-force sign convention detailed in Section 7.2.Answers: a) V = ____ kips b) V = ____ kips c) V = ____ kips Part 3: Determine the bending moment acting at each of the following locations:(a) x = 11.0 ft (i.e., at point B)(b) x = 28.5 ftNote that x = 0 at support A. When entering your answers, use the bending-moment sign convention detailed in Section 7.2. Answers: a) M = ____ kips-ft b) M = ____ kips-ft Part 4: Use your shear-force and bending-moment diagrams to determine the maximum bending moment, Mmax, and its location, xmax. Use the bending-moment sign convention detailed in Section 7.2.Answers: Mmax = ____ kips-ft xmax = ____ ft