Please help solve for I. (First photo for situational reference.) A child's top is held in place upright on a frictionlesssurface. The axle has a radius of r =2.46 mm. Two stringsare wrapped around the axle, and the top is set spinning byTTapplying T2.90 N of constant tension to each string. If ittakes 0.770 s for the string to unwind, how much angular2rmomentum L does the top acquire? Assume that the stringsdo not slip as the tension is applied.RL =kg-m?SIncorrect Point P is located on the outer surface of the top, a distanceh = 25.0 mm above the ground. The angle that the outersurface of the top makes with the rotation axis of the top is0 = 18.0°. If the final tangential speed v of point P is1.65 m/s, what is the top's moment of inertia I?T2rI =kg-m2Incorrect

a. the required angular momentum is τ=Lt2Tr=Lt22.9 N2.46×10-3 m=L0.77 sL=10.98×10-3 kgm2/s

Point P is located on the outer surface of the top, a distance h = 25.0 mm above the ground. The angle that the outer surface of the top makes with the rotation axis of the top is 0 = 18.0°. If the final tangential speed v, of point P is 1.65 m/s, what is the top's moment of inertia I? T 2r I = kg-m² Incorrect

Point P is located on the outer surface of the top, a distance h = 25.0 mm above the ground. The angle that the outer surface of the top makes with the rotation axis of the top is 0 = 18.0°. If the final tangential speed v, of point P is 1.65 m/s, what is the top's moment of inertia I? T 2r I = kg-m² Incorrect

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter11: Angular Momentum

Section: Chapter Questions

Problem 72P: An ice skater is preparing for a jump with turns and has his arms extended. His moment of inertia is...

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