1 point) Approximate cos(4.6) using a quadratic approximation:First note that cos(4.6) cos(3/2).Let f(x) = cos(x). Then,f'(x) = -sinxandf"(x) = -cosxLet a 3x/2. Then=f'(31/2) = -sin(3pi/2)andf" (3/2) = -cos(3pi/2)Q(x), the quadratic approximation to cos(x) at a = 3/2 is:Q(x) =Use Q(x) to approximate cos(4.6).cos(4.6) ≈B

Answered: Image /qna-images/answer/aeb7b35b-0559-45bd-9860-f1929877e91d.jpg

point) Approximate cos(4.6) using a quadratic approximation: First note that cos(4.6) cos(3/2). Let f(x) = cos(x). Then, f'(x) = -sinx and f"(x) = -cosx Let a = 3/2. Then f' (3/2) = -sin(3pi/2) and f" (3/2) = -cos(3pi/2) Q(x), the quadratic approximation to cos(x) at a = 3/2 is: Q(x) = Use Q(x) to approximate cos(4.6). cos(4.6)~

point) Approximate cos(4.6) using a quadratic approximation: First note that cos(4.6) cos(3/2). Let f(x) = cos(x). Then, f'(x) = -sinx and f"(x) = -cosx Let a = 3/2. Then f' (3/2) = -sin(3pi/2) and f" (3/2) = -cos(3pi/2) Q(x), the quadratic approximation to cos(x) at a = 3/2 is: Q(x) = Use Q(x) to approximate cos(4.6). cos(4.6)~

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter4: Calculating The Derivative

Section4.CR: Chapter 4 Review

Problem 2CR: Determine whether each of the following statements is true or false, and explain why. The derivative...

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