Please show the synthesis for the following compound C, from any alkane (compound A). Compound C IR spectrum is given below; 100 80 60 60 E 40 40 0 4000 3000 2000 1500 1000 400 IR2013-89280TK Wavenumber [cm] 20 20 Compound C has at least the following; 6 carbons 1 tertiary carbon 1 ring Compound B is an intermediate in the synthesis, please give all the possible isomers of compound B No stereocenters
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I need some guidance on what it is the following IR synthesis
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- Provide a structure for the compound with the formula C,H, NO using the given information. IR: 3360, 3280 cm (doublet); 1611 cm¯"; no carbonyl absorption; 'H NMR spectrum: chemical shift, Hz 1200 2400 2100 1800 1500 900 600 300 3H J = 6.9 Hz J= 6.9 Hz J = 8.7 Hz J = 8.7 Hz 4H 2H 2H 2H 8. 6. 4 chemical shift, ppm (8) 3 APR étv Aa MacBook AirPlease show the synthesis for the following compound C, from any alkane (compound A). Compound C IR spectrum is given below; 100 &T 80 60 40 20 0 4000 IR2013-89280TK 3000 2000 1500 Wavenumber [cm] Compound C has at least the following; 6 carbons 1 tertiary carbon 1 ring No stereocenters Munst 1000 Compound B is an intermediate in the synthesis, please give all the possible isomers of compound B 40010)Pyrrolium (1) and pyridinium (2) have markedly H different pK, values. Circle the compound with the lower pK₂ value. -N-H 11) The 1H NMR spectrum of phenol is shown below. Of note, the aryl proton signals resolve in this molecule. Assign protons to specific signals in the spectrum 8 7 6 H₂ H₁ 5 ppm H3 H₂ *CHCl3 2 H₁
- Please provide the IUPAC name (only) for the compound that best represents the spectroscopic data here: • Molecular formula: C4H100 Important IR data (cm 1): 3280 (broad); 2910-2950 (many); 1053 • All 'H NMR data shown as x.xx ppm (splitting), integration. 1.23 ppm (t), 3 1.23 ppm (d), 3 "-OH" 1.46 ppm (m), 2 4.03 ppm (m), 1 5. PPMHelp needed with the following C-NMR analysis on the molecule hexaphenylbenzene. Note: we can assume the ispo carbons for the central ring are downfield of those of the subtitients. "Ipso" standing for the aromatic carbon to which a susbstituent is attached. Thank you in advance!A carbon NMR spectrum has peaks at & 113 (1), 60 (2), and 15 (3). The numbers in the parentheses indicate the number of attached protons to each of the carbon signals. Explain why each of the following structures is NOT consistent with this spectrum. CH,OCH3 OCH,CH3 CH3OCH2-C-H CH3CH20-C-CH3 CH2OCH3 0-CH3
- This is the 13C RMN compound with molecular formula C9H18O. The compound reacts with 2,4-Dinitrophenylhydrazine but not with Tollens reactant. On the IR spectrum it has a stretch at 1710cm-1. What is the structure for the compound?4. Propose a structure for a compound, C4H7C1O2, that has the following IR and 'H NMR spectra : 100 80 60 - 40 - 20 - 4000 3500 3000 2500 2000 1500 1000 500 Wavenumber (cm- TMS 10 O ppm Chemical shift (6)Propose a structure for the alkene having the mass spectrum shown below. Assume that there are no double bond rearrangements occurring. M+ is at 84, major fragments at 69, 43, 41. Identify the major fragmentations/fragments using a proposed structure.. MASS SPECTRUM 100 80 60 - 40 20 - 0.0 0.0 20 40 60 80 100 m/z
- What peaks will appear in the IR spectrum of cyclopentanone (structure shown below)? O -1700 cm and -2900 cm1 O-1100 cm1 and -3200 cm 1 O -2700 cm1 and -3900 cm 1 O -1700 cm1 and -3300 cm1Reaction of C6H5CH2CH2OH with CH3COCl affords compound W, whichhas molecular formula C10H12O2. W shows prominent IR absorptions at3088–2897, 1740, and 1606 cm−1. W exhibits the following signals in its1H NMR spectrum: 2.02 (singlet), 2.91 (triplet), 4.25 (triplet), and 7.20–7.35(multiplet) ppm. What is the structure of W?The following ¹H NMR spectrum is shown in two questions. "nmrsim presentation" 1 1 C:\Bruker TopSpin3.5p17\examdata 10 1,4-Disubstituted benzene ring Which functional group is BEST attributed to the pair of doublets at about 7-8 ppm, each integrating to 2H? trans-alkene Cyclohexene Carboxylic acid [ppm] 1,3-Disubstituted benzene ring [oa]