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- The standard error of the mean (Qx) is a(n) estimate of population means which make up the sampling distribution. indication of variability in the distribution of sample means indication of variability in the raw data derived from the sample measure of variability in the populationMean and variance of marks of BSCS Section A are 62 and 16 respectively and that of BSSE Section B are 69 and 25 respectively, while the number of students are 30 and 40. Find out the combined mean. Which section has grater absolute dispersion? Which has greater relative dispersion?Distribution needed to calculate significance level
- 3:49 PM Sat Jan 30 MAT150 Online Assignment #1.docx Assignment #1 – How to use Calculator 1. If range is 60, number of class is 6, what is the class width? (Round up to next whole number) class width === 2. The data set is 2,4,5,7,10,15, what is sum Ex and the mean (Average)? (Round to the nearest tenth). Ex = 2+4+5+7+10+15 = (n is how many numbers there are) 3. If IQR is 0.69, find Usual Min and Usual Max? Usual Min = 0.68 – 1.5*IQR = Usual Max = 1.22 + 1.5*IQR = 4. Fill out the table below: H= 77.67 58 58 – 77.67 = -19.67 (-19.67)² = 386.9089 LL 5. Fill out the table below: x P(x) xP(x) x² x´p(x) 00.10 10.30 20.60 6. If , what is 7. If µ=5.5, o=0,1, n=16, what is a µ̟ and o̟? = 11 = *r. ==0 8. n= 150, o = 6,2, = 1 – 0.99 = 0.01, Z,= Z,005 = 2.575 SO0'0=1 pul Find 2.2 + E =. Find 2.2 – E =Using the appropriate model, sample size n, and output below: Model: y = Bo + B₂*₁ + B₂x₂ + B3x3 + Sample size: n=16 Regression Statistics Multiple R R Square Adjusted R Square Standard Error Observations ANOVA Regression Residual Total Total variation Unexplained variation Explained variation R^2 R-bar 2 (1) Report the total variation, unexplained variation, and explained variation as shown on the output. (Round your answers to 4 decimal places.) 0.9981 0.9962 0.9953 381.8582 16 SSE 8^2 DF ss 3 462,380,546.3200 1,749,788.0435 12 15 464,130,334.3635 (2) Report R² and R² as shown on the output. (Round your answers to 4 decimal places.) MS F 154,126,848.7733 1,056.9978 145,815.6703 F(model) (3) Report SSE, ², and s as shown on the output. Calculate s² from SSE and other numbers. (Round your answers to 4 decimal places.) Significance F 0.0000 (4) Calculate the Amodel) statistic by using the explained variation, the unexplained variation, and other relevant quantities. (Round your answer…pls include the variance
- 5a,the DV, statistical test, t-crit, and the blanks of the tablePlease show me your solutions and interpretations. Show the completehypothesis-testing procedure.A manufacturing company produces bearings. One line of bearings is specified to be 1.64 centimeters (cm) in diameter. A major customer requires that the variance of the bearings be no more than 0.001 cm2. The producer is required to test the bearings before they are shipped, and so the diameters of 16 bearings are measured with a precise instrument, resulting in the following values:1.69 1.62 1.63 1.70 1.66 1.63 1.65 1.71 1.64 1.69 1.57 1.64 1.59 1.66 1.63 1.65Assume bearing diameters are normally distributed. Use the data and α = 0.025 to test the data to determine whether the population of these bearings is to be rejected because of too high variance.A special bumper was installed on selected vehicles in a large fleet. The dollar cost of body repairs was recorded for all vehicles that were involved in accidents over a 1-year period. Those with the special bumper are the test group and the other vehicles are the control group, shown below. Each "repair incident" is defined as an invoice (which might include more than one separate type of damage). Statistic Test Group Control Group Mean Damage X¯¯¯1X¯1 = $ 1,153 X¯¯¯2X¯2 = $ 1,751 Sample Std. Dev. s1 = $ 663 s2 = $ 820 Repair Incidents n1 = 16 n2 = 14 Source: Unpublished study by Thomas W. Lauer and Floyd G. Willoughby. (a) Construct a 99 percent confidence interval for the true difference of the means assuming equal variances. (Round your final answers to 3 decimal places. Negative values should be indicated by a minus sign.) The 99% confidence interval is from to (b) Repeat part (a), using the assumption of unequal variances with Welch's…
- A special bumper was installed on selected vehicles in a large fleet. The dollar cost of body repairs was recorded for all vehicles that were involved in accidents over a 1-year period. Those with the special bumper are the test group and the other vehicles are the control group, shown below. Each "repair incident" is defined as an invoice (which might include more than one separate type of damage). Statistic Test Group Control Group Mean Damage X¯¯¯1X¯1 = $ 1,077 X¯¯¯2X¯2 = $ 1,800 Sample Std. Dev. s1 = $ 693 s2 = $ 814 Repair Incidents n1 = 16 n2 = 13 Source: Unpublished study by Thomas W. Lauer and Floyd G. Willoughby. (a) Construct a 90 percent confidence interval for the true difference of the means assuming equal variances. (Round your final answers to 3 decimal places. Negative values should be indicated by a minus sign.) The 90% confidence interval is from to (b) Repeat part (a), using the assumption of unequal variances with Welch's…A special bumper was installed on selected vehicles in a large fleet. The dollar cost of body repairs was recorded for all vehicles that were involved in accidents over a 1-year period. Those with the special bumper are the test group and the other vehicles are the control group, shown below. Each "repair incident" is defined as an invoice (which might include more than one separate type of damage). Statistic Test Group Control Group Mean Damage x¯1x¯1 = $ 1,101 x¯2x¯2 = $ 1,766 Sample Standard Deviation s1 = $ 696 s2 = $ 838 Repair Incidents n1 = 12 n2 = 9 (a) Construct a 90 percent confidence interval for the true difference of the means assuming equal variances. (Round answers to 3 decimal places. Negative values should be indicated by a minus sign.) (b) Repeat part (a), using the assumption of unequal variances with Welch's formula for d.f. (Round answers to 2 decimal places. Negative values should be indicated by a minus sign.) (d) Construct separate…Find μX and μY and also the variance with explanation pls
