Pedigree Analysis 1. Study the pedigree below and predict the genotypes and phenotypes possibilities of the five children in the third generation. This is for a sex-linked recessive trait. Normal Male Colorblind Male Normal Female Colorblind Female Identify the genotypes of all the individuals in the pedigree
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- . Jimsom. weed plants can produce purple or white flowers and spiny or smooth seed pods. A purple spiny plant is crossed with a white spiny plant. This cross produces: 89 purple spiny; 92 white spiny; 31 purple smooth and 27 white smooth plants. What are the genotypes of the parental plants and the progeny plants? Use the letters P/p for flower color and S/s for pod texture Parent #1 –genotype:_________________________________; Parent #2 –genotype: ______________________________ b. Offspring plants – genotypes and phenotypes c. Calculate the recombination frequency using these results_________________________________ i need help finding the right answer and i need an explation on how you got it so i understand and please do it with a punnet square and show the calutions step by stepNotes Bell Work Assignments Pedigree Chart Key How many females are carriers? |JO - Unaffected How many affected males are there? TO Carrier Complete a Punnett Square for the cross in the F4 generation. 10 Affected The affectedallele is recessive I Could the male in the F5 generation be affected? Could he be a carrier? If 'yes', what chance does he have of being affected? Of being a carrier? (answer is a fraction out of 4) Type here to search W BrSe www.on ican webteMSTUARTL 192 Inheritance AO Multiple Alleles in Blood Groups The four common blood groups of the human 'ABO blood group system' are determined by three alleles: A, B, and o (also represented in some textbooks as: 1ª, 1®, and ¡º or just i). This is expressed equally. They each produce a different functional an example of a multiple allele system for a gene. The ABO enzyme that adds a different, specific sugar to the basic sugar antigens consist of sugars attached to the surface of red blood molecule. The blood group A and B antigens are able to react cells. The alleles code for enzymes (proteins) that join together with antibodies present in the blood from other people and must these sugars. The allele O produces a non-functioning enzyme that is unable to make any changes to the basic antigen (sugar molecule. The other two alleles (A, B) are codominant and are be matched for transfusion. Recessive allele: O produces a non-functioning protein Dominant allele: A…
- 11 Normal No Spac. Styles Paragraph Inheritance APPLICATION Imagine that you are interested in developing a new tomato plant that will inchude the large size and sweetness from one parent and yellow color from another parent. The first parent plant has bland-tasting small yellow tomatoes and the other parent has sweet-tasting large red tomatoes. The chromosomes and alleles of the two plants are shown below. Plant #1: Bland (B), Small (1), Yellow (r) Plant #2: Sweet (b), Large (L), Red (R) R 1 r R Think about what you learned about inheriting traits from the lab to answer these questions. 1. Explain (in sentence form) why it is or is not possible for any of the offspring of these parents to have the sweet gene expressed in its phenotype. To illustrate your explanation, you may use a diagram or use the Punnett squares below to show the genotypes of the possible offspring. Include a percent chance in your answer. 2. Explain whether or not it is possible to create a tomato plant with…For numbers 34-50. Given the following pedigree, answer the following questions. 1st generation would be the grandparents, 2" generation would be the children of the grandparents and the 3" generation would be the children of the 2"generation. Trait that would be track is autosomal dominant and recessive. Cleft chin (CC or Ce) = Dominant No cleft chin (ce) = Recessive II 10 34-37. What is the expected Genotype of the grandfather? A. CC В. Се С. се D. Either A or B 38-41. What is the expected genotype of number 4 given the following genes in the 1st generation A. CC В. Се C. Either A or B D. Neither A nor 8 42-45. Who are the persons failed to inherit cleft chin from the grand mother? A. Number 5, 1, 8,9 and 7 B. Number 2, 9, 7, 10 and 3 C. Number 2, 5, 7, and 9 D. Number 1, 3 and 10 E. Nurmber 2 and 5 47-50. If number 10 married a person without a cleft chin and all the off-springs have cleft chin, what is the genotype of number 10? A C В. Сс С. сс D. Either A nor B1 pts The pedigree below shows the expression of Huntington's disease in a family. Huntington's disease is a fatal genetic disorder that causes the progressive breakdown of nerve cells in the brain. It deteriorates a person's physical and mental abilities usually during their prime working years and has no cure. Huntington's is inherited as a dominant allele (H). Examine the pedigree below and determine the genotype for individual "2" DODO0O 2. O HH O Hh О h O either HH or Hh
- 2/7 - <. Hair texture is an incompletely dominant trait in humans. The three phenotypes are curly, wavy and straight. Straight only occurs when both parents have straight hair. Curly hair also tends to follow this pattern. Only two wavy haired parents produce all three phenotypes. Please explain this observation using punnett squares. Curly x Curly straight x straight Wavy x wavyFor numbers 34-50. Given the following pedigree, answer the following questions. 1st generation would be the grandparents, 2" generation would be the children of the grandparents and the 3" generation would be the children of the 2" generation. Trait that would be track is autosomal dominant and recessive. Cleft chin (CC or Ce) = Dominant No cleft chin (cc) = Recessive II II 10 42-45. Who are the persons failed to inherit cleft chin from the grand mother? A. Number 5, 1, 8,9 and 7 B. Number 2, 9, 7, 10 and 3 C. Number 2, 5, 7, and 9 D. Number 1, 3 and 10 E. Number 2 and 5olving Monohybrid Inheritance single gene. crosses. The henotypic traits controlled by a single gene. The problems are to give you practice in problem solving using Mendelian genetics. A dominant gene (W) produces wire-haired texture in dogs; its recessive allele (w) produces smooth hair. A group of heterozygous wire-haired individuals are crossed and their F1 progeny are then test-crossed. Determine the expected genotyplc and phenotypic ratios among the test cross progeny:
- re ||| E 6. Label the genotypes for this pedigree of an X-linked recessive disorder (red- green colorblindness). (a) 2 2 3 1 3 a. How do you know? b. Label the genotypes. 4 O To 2 4 5 5 6 6 7. Is the following pedigree autosomal recessive, autosomal dominant or X-linked recessive? 2 8 O T 58Brown eyes are dominant over blue. This is NOTA sex-linked trait. If a blue-eyed colorblind woman marries a normal visioned man who is homozygous for brown eye color, what kind of children might they expect with respect to these two traits? 5. Genotype of woman _Genotype of man What two genotypes are possible in the children? If one of the sons in turn marries a heterozygous brown-eyed, normal visioned woman, not a carrier, what kinds of children might they expect? Genotypes Phenotypesa. The ability to taste the chemical phenylthiocarbamideis an autosomal dominant phenotype, and the inabilityto taste it is recessive. If a taster woman with a nontasterfather marries a taster man who in a previous marriagehad a nontaster daughter, what is the probability thattheir first child will be(1) A nontaster girl(2) A taster girl(3) A taster boyb. What is the probability that their first two childrenwill be tasters of either sex?