Part B. Standardization of Sodium hydroxide solution Balanced chemical equation: Trial 1 Trial 2 Trial 3 Mass of oxalic acid 0.1314g NA NA Initial burette reading 0.40mL Final burette reading 20.60 mL -0.40 mL 20.20 mL 20.60mL Volume NaOH added 20.20mL moles of oxalic acid 0:001m O.1314 3 = 0.00Im moles of NaOH added 0.002 m 2x 0.001m=0.002 Molarity of NaOH 0.IM

Chemistry
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ISBN:9781133611097
Author:Steven S. Zumdahl
Publisher:Steven S. Zumdahl
Chapter16: Solubility And Complex Ion Equilibria
Section: Chapter Questions
Problem 10RQ: Figure 15-3 outlines the classic scheme for separating a mixture of insoluble chloride salts from...
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Experiment 11
Data to be completed and uploaded.
Only one trial!
(There is no part A)
Part B. Standardization of Sodium hydroxide solution
Balanced chemical equation:
Trial 1
Trial 2
Trial 3
Mass of oxalic acid
_0.1314g_
NA
NA
Initial burette reading
_0.40mL
Final burette reading
20.60 me
-0.40 mL
20.20 mL
Volume NaOH added
20.60mL
· 20.20m
moles of oxalic acid
0:001m
O.1314 g
molcs
= 0.00Im
う11*メP
moles of NaOH added
90g
Actd
0.002 m
2x 0.00lm=0.002
Molarity of NaOH
0.IM
oF NaOH=welas
Volume
molavit
2020ML
Transcribed Image Text:Experiment 11 Data to be completed and uploaded. Only one trial! (There is no part A) Part B. Standardization of Sodium hydroxide solution Balanced chemical equation: Trial 1 Trial 2 Trial 3 Mass of oxalic acid _0.1314g_ NA NA Initial burette reading _0.40mL Final burette reading 20.60 me -0.40 mL 20.20 mL Volume NaOH added 20.60mL · 20.20m moles of oxalic acid 0:001m O.1314 g molcs = 0.00Im う11*メP moles of NaOH added 90g Actd 0.002 m 2x 0.00lm=0.002 Molarity of NaOH 0.IM oF NaOH=welas Volume molavit 2020ML
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