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- Simplify the following Boolean function and expression, using four-variable maps a) cF(w,x,y,z) = Σ (2,3,10,11,12,13,14,15) b) dF = x’z + w’xy’ + w(x’y + xy’) c) eF = A’B’C’D’+AC’D’+B’CD’+A’BCD+BC’Duse k map to simplify the sum of products expansion: wxyz+ wxyz' + wxy'z' +wx'yz+wx'y'z+wx'y'z'+w'xy'z+w'x'yz+w'x'yz'Create the Kmaps and then simplify for the following functions (leave in sum-of-products form): a) F(w,x,y,z) = w'x'y'z' + w'x'yz' + w'xy'z + w'xyz + w'xyz' + wx'y'z' + wx'yz' b) F(w,x,y,z) = w'x'y'z + w'x'yz' + w'xy'z + w'xyz + w'xyz' + wxy'z + wxyz + wx'y'z
- Create the K-maps and then simplify for the following functions (leave in sum-of-products form): F(w,x,y,z) = w′x′y′z + w′x′yz′+ w′xy′z + w′xyz + w′xyz′ + wxy′z + wxyz + wx′y′z F(w,x,y,z) = w′x′y′z′ + w′z + w′x′yz′ + w′xy′z′+ wx′y4. Simplify the following Boolean expressions, using four-variable K-maps: (a) A′B′C′D′+AC′D′+B′CD′+A′BCD+BC′D (b) w′z+xz+x′y+wx′zSimplify the following Boolean expressions, using four-variable maps: (a) A'B'C'D' + AC'D' + B'CD' + A'BCD + BC'D (b) x'z + w'xy' + w(x'y + xy') (c) A'B'C'D + AB'D + A'BC' + ABCD + AB'C
- Using k map simplify the following Boolean function f(x,y,z) = x ȳ z + x ȳ z̄ + x̄ y z + x̄ ȳ z + x̄ ȳ z̄Create the Kmap and then simplify for the functions (leave in sum-of-products form): F(w, x, y, z) = w′x′y′z′ + w′x′yz′ + w′xy′z + w′xyz + w ′xyz′ + wx′y′z′ + wx′yz′What is F in SOP in expression F(w,x ,y z) = Σ(2, 4, 6, 8, 10, 12): d(0, 1, 3, 5, 7, 9, 11, 13, 14, 15) a. 1 b. F = (wx) + (yz) c. F = (xyz) + (wz) + (yz) d. F = (wy) + (xz)
- Use K-Maps to simplify each of the following: ~x~y~z + ~xyz + ~xy~z ~x~y~z + ~xy~z + x~y~z + xy~z ~y~z + ~yz + xy~zPlease explain all stepsTrue/False: a) There exists a mapping reduction from ETM to EDFA. b) There exists a mapping reduction from ATM to ETM. c) There exists a mapping reduction from ECFG to EQTM.PLEASE EXPLAIN ALL STEPS (including how k-map formation is formed): simplify the boolean equations: xz + (xy + ~z) ~xyz + yz + x~y