non-negative and non-zero integer number and name it c0; 2. if it's even, evaluate a new c0 as c0 ÷ 2; 3. otherwise, if it's odd, evaluate a new c0 as 3 × c0 + 1; 4. if c0 ≠ 1, skip to point 2. The hypothesis says that regardless of the initial value of c0, it will always go to 1. Of course, it's an extremely complex task to use a computer in order to prove the hypothesis for any natural number (it may even need artificial intelligence), but you can use Python to check some individual numbers. Maybe you'll even find the one which would disprove the hypothesis. Write a program which reads one natural number and executes the above steps as long as c0remains different from 1(c0 != 1). Moreover, we'll add another task - we want you to count the steps needed to achieve the goal. Your code should output all the intermediate values of c0, too. Hint: the most important part of the problem
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I have a python programing question
In 1937, a German mathematician named Lothar Collatz formulated an intriguing hypothesis (it still remains unproven) which can be described in the following way:
The hypothesis says that regardless of the initial value of c0, it will always go to 1.
Of course, it's an extremely complex task to use a computer in order to prove the hypothesis for any natural number (it may even need
Write a
Hint: the most important part of the problem is how to transform Collatz's idea into a while loop - this is the key to success.
Example input
15
Example output
46 23 70 35 106 53 160 80 40 20 10 5 16 8 4 2 1 steps = 17.l
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