MH Design a 256KB (note the B) direct-mapped data cache that uses a 32-bit data and address and 8 words per block. Calculate the following: (a) How many bits are used for the byte offset and why? 1 0 29 The byte offset needs 5 bits to address each byte within a block because 2^5 = 32_ (b) How many bits are used for the set (index) field? We will need 13 bits for the set (index)_ (c) How many bits are used for the tag? 32-5-13 14 bits_ (d) What's the overhead for that cache? 2^13 X 14 = 114688 bits__ (e) How is the address divided, label below? 200 JN 8 7 2222 NN HN 2 1 ON 9 8 HD 6 15 1 WH NH 3 2 1 1 HO 1 9 60 10 44 m N O

MH Design a 256KB (note the B) direct-mapped data cache that uses a 32-bit data and address and 8 words per block. Calculate the following: (a) How many bits are used for the byte offset and why? 1 0 29 The byte offset needs 5 bits to address each byte within a block because 2^5 = 32_ (b) How many bits are used for the set (index) field? We will need 13 bits for the set (index)_ (c) How many bits are used for the tag? 32-5-13 14 bits_ (d) What's the overhead for that cache? 2^13 X 14 = 114688 bits__ (e) How is the address divided, label below? 200 JN 8 7 2222 NN HN 2 1 ON 9 8 HD 6 15 1 WH NH 3 2 1 1 HO 1 9 60 10 44 m N O

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Description: help check the answer and do the last problem please 1Design a 256KB (note the B) direct-mapped data cache that uses a 32-bit data and address and 8 words per block.Calculate the following:(a) How many bits are used for the byte offset and why?The by

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter6: System Integration And Performance

Section: Chapter Questions

Problem 22VE

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