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Q: What is the magnitude of the force a +21 μC charge exerts on a +3.0 mC charge 37 cm away?
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- A 75.0-g arrow, fired at a speed of 110 m/s to the left, impacts a tree, which it penetrates to a depth of 12.5 cm before coming to a stop. Assuming the force of friction exerted by the tree is constant, what are the magnitude and direction of the friction force acting on the arrow?The 137-lb force P is applied to the 240-lb crate, which is stationary before the force is applied. Determine the magnitude and direction of the friction force F exerted by the horizontal surface on the crate. The friction force is positive if to the right, negative if to the left. Assume μ = 0.51, Mk = 0.39. P Answer: F = i Mk lbThe 118-lb force P is applied to the 250-lb crate, which is stationary before the force is applied. Determine the magnitude and direction of the friction force F exerted by the horizontal surface on the crate. The friction force is positive if to the right, negative if to the left. Assume ??= 0.48, ??= 0.38.
- The 121-lb force P is applied to the 250-lb crate, which is stationary before the force is applied. Determine the magnitude and direction of the friction force F exerted by the horizontal surface on the crate. The friction force is positive if to the right, negative if to the left. Assume μ = 0.45, μk = 0.36. Answer: F= i lbWhile digging a small hole prior to planting a tree, a homeowner encounters rocks. If he exerts a horizontal 239-N force on the prybar as shown, what is the horizontal force exerted on rock C? Note that a small ledge on rock C supports a vertical force reaction there. Neglect friction at B. Complete solutions (a) including and (b) excluding the weight of the 17-kg prybar. A 239 N 1550 mm 16° B 230 mm Answers: (a) Including weight, Fc- i (a) Excluding weight, Fe- i Nmoodle.nct.eduom/mod/qi -Learning Portal Courses - Reports - e-Services- Academic Departments - ETC - CIMS - A 17kg crate resting on a horizontal surface is pushed as shown. If the coefficient of static friction u, between the surfaces is 0.24, what is the minimum force (F) required to start the motion? O a 4.08N O b. 70.83N Oc 39.98N Od. 694.17N Windows buut An object of mass Skg is sliding with a constant velocity of 10m/s on a frcitionless horizontal table. The force needed to keep the object moving with the same velocity is. 144 4- # 4. 6. V.
- Côncept Example 9. A 225-kg crate rests on a surface that is inclined em are presented in Multiple- above the horizontal at an angle of 20.0°. A horizontal force (magnitude 535 N and parallel to the ground, not the incline) is required to start the into solving crate moving down the incline. What is the coefficient of static friction s an angle of hetic friction * initial speed between the crate and the incline? 119. The drawing shows a 25.0-kg crate that 球 Is initially at rest. Note that the view is one look- ing down on the top of the crate. Two forces, F, and F, are applied to the crate, and it begins to +y does the box 2- move. The coefficient of kinetic friction =0.350. 55.0 es, a force of 54.0 N F, between the crate and the floor is u = current of the Determine the magnitude and direction (relative Top view of east. When in a direction to the x axis) of the acceleration of the crate. ADN (NG N 88.0 NA push of magnitude P acts on a box of weight W as shown in the figure. The push is directed at an angle 0 below the horizontal, and the box remains a rest. The box rests on a horizontal surface that has some friction with the box. The normal force on the box due to the floor is equal to: O W + P cos 0. O W + P sin 0. OW-P sin 0. O W + P. O W. W 0 PQuestion 1 2 pts Which direction does the normal force on the point in? M Ms Mx O Impossible to determine Directly upward Angle 0 from the horizontal Angle 0 from the vertical
- A 250.0 N box is placed on a horizontal surface and a force of 150 N is applied at anangle of 30.0o from the horizontal. As a result, the box slides along the surface with anacceleration of 05.00 m/s2What is the coefficient of friction between the box and the surface?Problem 2: Determine the force P necessary to start the V-shaped wedge to the right if the coefficient of friction is f= 0.445 at each of the three surfaces of contact. Wg =1000N WA =200N в P- 30° 150Fnorm Fapp = 15 N арp 45° Firiet =- 5 kg gray Assuming that the 5-kg object experience no net force (in equilibrium). the following values will be Fnorm Fgrav = Coefficient of kinetic friction u = O Fnorm = 60.4 N, Ferav = 49.0 N, Coefficient of kinetic friction uk = 0.25. O Fnorm = 38.4 N. Fe =49.0 N. Coefficient of kinetic friction u = 0.28. %3D grav O Fnorm = 49.0 N, Fgrav = 49.0 N, Coefficient of kinetic friction u = 0.22. Fnorm = 9.8 N, Ferav = 98.0 N, Coefficient of kinetic friction u = 0.56. Next