Lonely Ones Binary ones (1) can get lonely if only zeros (0) surround them. Formally, we call such 1's "sparse". A number is defined as sparse if its binary representation has no two consecutive bits set. You are given an integer N and your task is to find out if it is sparse or not. Input The input contains an integer N. Output Print '1' if the number is sparse and '0' if the number is not sparse. Constraints 1 <= N <= 1018

Lonely Ones Binary ones (1) can get lonely if only zeros (0) surround them. Formally, we call such 1's "sparse". A number is defined as sparse if its binary representation has no two consecutive bits set. You are given an integer N and your task is to find out if it is sparse or not. Input The input contains an integer N. Output Print '1' if the number is sparse and '0' if the number is not sparse. Constraints 1 <= N <= 1018

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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in java lanuage please You have been given two sorted arrays (in increasing order), find a path through the intersectionsthat produces maximum sum and return the maximum sum.That is, you can switch from one array to another array only at common elements.If no intersection element is present, we need to take sum of all elements from the array with greatersum.Input Format:Line 1: Size of first arrayLine 2: Elements of first arrayLine 3: Size of second arrayLine 4: Elements of second arrayOutput Format:The maximum sumSample Input:61 5 10 15 20 2552 4 5 9 15Sample Output:81Explanation:We will start from second array and take sum till 5 which will be equal to 11. Then we'll switch tofirst array because both arrays are intersecting at 5 so then we will start from element 10 and take till15 and the sum will become 36. Now again both arrays are intersecting at 15 but there are noelements left in second array after 15, so we'll continue with first array. Hence sum will be 81. in java
solve in java Integer arrays originalArr and filterArr are read from input, each containing two elements. If an element in originalArr is not a multiple of the corresponding element in filterArr, replace the element in originalArr with the corresponding element in filterArr times 2. Ex: If the input is: 16 9 8 4 then the output is: 16 8 Note: Given integers A and B, A is a multiple of B only if A % B == 0. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 import java.util.Scanner; public class ReplaceNumbers { publicstaticvoidmain(String[] args) { Scannerscnr=newScanner(System.in); finalintNUM_VALS=2; int[] originalArr=newint[NUM_VALS]; int[] filterArr=newint[NUM_VALS]; inti; for (i=0; i<NUM_VALS; ++i) { originalArr[i] =scnr.nextInt(); } for (i=0; i<NUM_VALS; ++i) { filterArr[i] =scnr.nextInt(); } /* Your code goes here */ for (i = 0; i < originalArr.length; ++i) { System.out.print(originalArr[i] + " "); } System.out.println();…
The Problem The Mastermind game board game is a code breaking game with two players. One player (your program) becomes the codemaker, the other the codebreaker. The codemaker (your program) creates a 4 digit secret code which is randomly generated by the supplied code below and the codebreaker tries to guess the 4 digit pattern. import randomsecretCode =[]for i in range (0,4): n = random.randint(1,9) secretCode.append(str(n)) print (secretCode) # take this out when you are playing the game for real because it is a secret The secret code pattern generated above will consist of any of the digits 1-9 and can contain multiples of the same digit. Your program should then tells the codebreaker which digits should be in their guess by displaying a sorted list of the digit characters contained in the secret code python list . Use the loopfor digit in sorted(secretCode): #display each digit on the same line for the player to see; there could be duplicate digits in the secret Prompt…
Up for the count def counting_series(n): The Champernowne word 1234567891011121314151617181920212223... is an infinitely long string of digits made up of all positive integers written in ascending order without any separators between the individual numbers. This function should return the integer digit that lies in the position n of the Champernowne word, position count again starting from zero as usual. Of course, the automated tester will give your function values of n large enough that anybody trying to solve this problem by explicitly constructing the series as a string would run out of time and space long before receiving the answer. Instead, you should observe that the structure of this infinite sequence is quite straightforward, as it starts with 9 single-digit numbers, followed by 90 two-digit numbers, followed by 900 three-digit numbers, and so on. Such a predictably self-similar structure allows you to skip over prefixes of this series in exponentially widening leaps and…
Up for the count def counting_series(n): The Champernowne word 1234567891011121314151617181920212223... is an infinitely long string of digits made up of all positive integers written in ascending order without any separators between the individual numbers. This function should return the integer digit that lies in the position n of the Champernowne word, position count again starting from zero as usual.Of course, the automated tester will give your function values of n large enough that anybody trying to solve this problem by explicitly constructing the series as a string would run out of time and space long before receiving the answer. Instead, you should observe that the structure of this infinite sequence is quite straightforward, as it starts with 9 single-digit numbers, followed by 90 two-digit numbers, followed by 900 three-digit numbers, and so on. Such a predictably self-similar structure allows you to skip over prefixes of this series in exponentially widening leaps and…
Correct answer will be upvoted else Multiple Downvoted. Don't submit random answer. Computer science. Ridbit begins with an integer n. In one action, he can perform one of the accompanying tasks: partition n by one of its appropriate divisors, or take away 1 from n in case n is more prominent than 1. An appropriate divisor is a divisor of a number, barring itself. For instance, 1, 2, 4, 5, and 10 are appropriate divisors of 20, however 20 itself isn't. What is the base number of moves Ridbit is needed to make to decrease n to 1? Input The principal line contains a solitary integer t (1≤t≤1000) — the number of experiments. The main line of each experiment contains a solitary integer n (1≤n≤109). Output For each experiment, output the base number of moves needed to lessen n to 1.
You are a movie theater manager. You are given a two-dimensional array with 6 rows and 6 columns - 36 elements with O value, that represent empty theater seats. All 36 tickets for session were sold, so you need to identify all of the seats with value 1. Write a program that replaces all O values in the given array, by 1 and outputs the resulting matrix. Use nested for-loops to iterate over two-dimensional matrix.
in Python Minima in permutations. Write a program that takes an integer n from the command line, generates a random permutation, prints the permutation, and prints the number of left-to-right minima in the permutation (the number of times an element is the smallest seen so far). Then write a program that takes integers m and n from the command line, generates m random permutations of length n, and prints the average number of left-to-right minima in the permutations generated
Task is to generate a list of 100 random integers between 1 and 1000. The integers should be sorted from smallest to largest and have no duplicates. Your code should perform at most n operations, where n = 100 in this case. What this means is that your random generation function random.randint(x,y) should not be called more than 100 times.
A wrestling tournament has 256 players. Each match includes 2 players. The winner each match will play another winner in the next round. The tournament is single elimination, so no one will wrestle after they lose. The 2 players that are undefeated play in the final game, and the winner of this match wins the entire tournament. How would you determine the winner? Here is one algorithm to answer this question. Compute 256/2 = 128 to get the number of pairs (matches) in the first round, which results in 128 winners to go on to the second round. Compute 128/2 = 64, which results in 64 matches in the second round and 64 winners, to go on to the third round. For the third round compute 64/2 = 32, so the third round has 64 matches, and so on. The total number of matches is 128 + 64 + 32+ .... Finish this process to find the total number of matches.
The SparseVector class should be extended to include a method sum() that accepts a SparseVector as an argument and returns a SparseVector that represents the term-by-term total of the input and output vectors. Note: To handle the situation where an entry becomes 0, you must use delete() (and pay close mind to precision).use java to code
solve in java Integer arrays groceryItemPrices and stockRecords are read from input, containing the prices and stock records of each grocery item. Initialize variable count with 0. For each grocery item, increment count if a grocery item meets both of the following conditions: Price is greater than 20. Stock record is less than 20. Lastly, output count followed by a newline. Ex: For the input: 28 14 21 22 7 9 17 24 18 10 20 26 then the output is: 3 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 import java.util.Scanner; public class CombineArrays { publicstaticvoidmain(String[] args) { Scannerscnr=newScanner(System.in); finalintNUM_VALS=6; int[] groceryItemPrices=newint[NUM_VALS]; int[] stockRecords=newint[NUM_VALS]; inti; intcount; for (i=0; i<NUM_VALS; ++i) { groceryItemPrices[i] =scnr.nextInt(); } for (i=0; i<NUM_VALS; ++i) { stockRecords[i] =scnr.nextInt(); } /* Your code goes here */