Java programming See attached The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a String rather than an Integer. At FIXME in the code, add a try/catch statement to catch java.util.InputMismatchException, and output 0 for the age. import java.util.Scanner; import java.util.InputMismatchException; public class NameAgeChecker {    public static void main(String[] args) {       Scanner scnr = new Scanner(System.in);       String inputName;       int age;              inputName = scnr.next();       while (!inputName.equals("-1")) {          // FIXME: The following line will throw an InputMismatchException.          //        Insert a try/catch statement to catch the exception.          age = scnr.nextInt();          System.out.println(inputName + " " + (age + 1));                    inputName = scnr.next();       }    } }

C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter12: Points, Classes, Virtual Functions And Abstract Classes
Section: Chapter Questions
Problem 22SA
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Java programming

See attached

The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a String rather than an Integer. At FIXME in the code, add a try/catch statement to catch java.util.InputMismatchException, and output 0 for the age.

import java.util.Scanner;
import java.util.InputMismatchException;

public class NameAgeChecker {
   public static void main(String[] args) {
      Scanner scnr = new Scanner(System.in);

      String inputName;
      int age;
      
      inputName = scnr.next();
      while (!inputName.equals("-1")) {
         // FIXME: The following line will throw an InputMismatchException.
         //        Insert a try/catch statement to catch the exception.
         age = scnr.nextInt();
         System.out.println(inputName + " " + (age + 1));
         
         inputName = scnr.next();
      }
   }
}

Ex: If the input is:
Lee 18
Lua 21
Mary Beth 19.
Stu 33
-1
then the output is:
Lee 19
Lua 22
Mary 0
Stu 34
Transcribed Image Text:Ex: If the input is: Lee 18 Lua 21 Mary Beth 19. Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34
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