What can you conclude about the data? OA. Reject Ho. At the 1% level of significance, there is sufficient evidence to reject the claim that the difference in mean annual salaries is $10,000. B. Fail to reject Ho. At the 1% level of significance, there is sufficient evidence to reject the claim that the difference in mean annual salaries is $10,000. OC. Reject Ho. At the 1% level of significance, there is insufficient evidence to reject the claim that the difference in mean annual salaries is $10,000. OD. Fail to reject Ho. At the 1% level of significance, there is insufficient evidence to reject the claim that the difference in mean annual salaries is $10,000. Is the difference between the mean annual salaries of entry level architects in Denver, Colorado, and Lincoln, Nebraska, equal to $10,000? To decide, you select a random sample of entry level architects from each city. The results of each survey are shown. Assume the population standard deviations are o₁ = $6508 and 02 = $6285. At a = 0.01, what should you conclude? Entry level architects in Denver, CO x₁ = 58,300 Entry level architects in Lincoln, NE x2 = 54,240 n₁ = 30 Calculate the standardized test statistic. z= (Round to two decimal races as needed.) Determine the P-value. The P-value is (Round to three decimal places as needed.) What can you conclude about the data? n2 = 39

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 13PPS
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What can you conclude about the data?
OA. Reject Ho. At the 1% level of significance, there is sufficient evidence to reject the claim that the difference in mean annual salaries is $10,000.
B. Fail to reject Ho. At the 1% level of significance, there is sufficient evidence to reject the claim that the difference in mean annual salaries is $10,000.
OC. Reject Ho. At the 1% level of significance, there is insufficient evidence to reject the claim that the difference in mean annual salaries is $10,000.
OD. Fail to reject Ho. At the 1% level of significance, there is insufficient evidence to reject the claim that the difference in mean annual salaries is $10,000.
Transcribed Image Text:What can you conclude about the data? OA. Reject Ho. At the 1% level of significance, there is sufficient evidence to reject the claim that the difference in mean annual salaries is $10,000. B. Fail to reject Ho. At the 1% level of significance, there is sufficient evidence to reject the claim that the difference in mean annual salaries is $10,000. OC. Reject Ho. At the 1% level of significance, there is insufficient evidence to reject the claim that the difference in mean annual salaries is $10,000. OD. Fail to reject Ho. At the 1% level of significance, there is insufficient evidence to reject the claim that the difference in mean annual salaries is $10,000.
Is the difference between the mean annual salaries of entry level architects in Denver, Colorado, and Lincoln, Nebraska, equal to $10,000? To decide, you select a
random sample of entry level architects from each city. The results of each survey are shown. Assume the population standard deviations are o₁ = $6508 and
02 = $6285. At a = 0.01, what should you conclude?
Entry level architects
in Denver, CO
x₁ = 58,300
Entry level architects
in Lincoln, NE
x2 = 54,240
n₁ = 30
Calculate the standardized test statistic.
z=
(Round to two decimal races as needed.)
Determine the P-value.
The P-value is
(Round to three decimal places as needed.)
What can you conclude about the data?
n2 = 39
Transcribed Image Text:Is the difference between the mean annual salaries of entry level architects in Denver, Colorado, and Lincoln, Nebraska, equal to $10,000? To decide, you select a random sample of entry level architects from each city. The results of each survey are shown. Assume the population standard deviations are o₁ = $6508 and 02 = $6285. At a = 0.01, what should you conclude? Entry level architects in Denver, CO x₁ = 58,300 Entry level architects in Lincoln, NE x2 = 54,240 n₁ = 30 Calculate the standardized test statistic. z= (Round to two decimal races as needed.) Determine the P-value. The P-value is (Round to three decimal places as needed.) What can you conclude about the data? n2 = 39
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