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Using the following schemaƟc connecƟons write the code such that the circuit meet the following
criteria:
1. If push button 1 is pressed LED 1 turns on only. Everything else should be off.
2. If push button 2 is pressed piezo speaker should play tone 500 for ½ sec and LED 5 turns on.
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- Typed plzzzz AsapPLEASE PLEASE SHOW CALCULATIONS Using the Vigenere cipher given in class: ADQYS MIUSB OXKKT MIBHK IZOOO EQOOG IFBAG KAUMFVVTAA CIDTW MOCIO EQOOG BMBFV ZGGWP CIEKQ HSNEWVECNE DLAAV RWKXS VNSVP HCEUT QOIOF MEGJS WTPCHAJMOC HIUIX Determine the Keys that would be needed to decipher the given cipher given the following deductions made in class Key of length 6; alphabet 1: AIKHOIATTOBGEEERNEOSAI alphabet 2: DUKKEFUAWEMGKWDWSUFWJU alphabet 3: QSTIQBMAMQBWQVLKVTMTMI alphabet 4: YBMZOAFCOOFPHEAXPQEPOX alphabet 5: SOIOOGVICOVCSVASHOGCC alphabet 6: MXBOGKVDIGZINNVVCIJHHerhjrthnd
- 7) Find the esuts nsteps 8 << 98812 0 13 g ) By sing FORloopsand F crestamattx D, O=| 3 1 3 3 8 =1 PO ... AurgwntIt will simulate the diffusion of heatthrough a square metal plate. The plate starts off at 0 deg., but the 4 ×4 pixel square in the centeris kept at 100 deg.Now a cell in the interior has 4 neighbors: the upper, lower, left, and right neighbor. The updateformula for an interior point (other than the center square) is therefore given by:u′i,j = ui,j + k((ui,j+1 −ui,j ) + (ui,j−1 −ui,j ) + (ui−1,j −ui,j ) + (ui+1,j −ui,j ))= ui,j + k(ui,j+1 + ui,j−1 + ui−1,j + ui+1,j −4ui,j )The boundaries have to be updated separately using 8 different equations: 4 for each of the edges,and 4 for each corner. Here is the update formula for a cell on the top edge that is not on a corner:u′i,n−1 = ui,n−1 + k((ui,n−2 −ui,n−1) + (ui−1,n−1 −ui,n−1) + (ui+1,n−1 −ui,n−1))= ui,n−1 + k(ui,n−2 + ui−1,n−1 + ui+1,n−1 −3ui,n−1)Here is the update formula for a cell in the top left corner:u′0,n−1 = u0,n−1 + k((u0,n−2 −u0,n−1) + (u1,n−1 −u0,n−1))= u0,n−1 + k(u0,n−2 + u1,n−1 −2u0,n−1) Program:
- Look at the following applet code snippet: 1 import javax.swing.*; 2 import java.awt.*; 3 public class GraphicsTest extends JApplet 4 { 5 public void init() 6 { 7 getContentPane().setBackground(Color.WHITE); 8 } 9 public void paint(Graphics g) 10 { 11 int[] xCoords = {20, 20, 60, 100, 140, 140, 100, 60}; 12 int[] ycoords = {20, 100, 140, 140, 100, 60, 20, 20}; 13 super.paint(g); 14 g.setColor(Color.YELLOW); 15 g.fillPolygon(xCoords, yCoords, 8); 16 g.setColor(color.BLACK); 17 g.setFont(new Font("SansSerif", Font.BOLD, 35)); 18 g.drawString("SLOW", 35, 95); 19 } 20 } How many vertices does the polygon have? Justify your answer.Condense the expression 4ln(c) + ln(d) + ln(a )/3 + ln(b _+ 3) /3 to a single logaithm.Hi there, I have to write apache kafka in java for 3 consumers. Currently I have code for 1 but i am struggling to make it to 3 consumers. Can anyone change it so that it runs with 3 consumers. consumer.java is as follows import org.apache.kafka.clients.consumer.ConsumerRecord;import org.apache.kafka.clients.consumer.ConsumerRecords;import org.apache.kafka.clients.consumer.KafkaConsumer;import java.time.Instant;import java.util.ArrayList;import java.util.List;import java.util.Properties;import java.time.Instant;public class Consumer {public static void main(String[] args) {Properties properties = new Properties();properties.put("bootstrap.servers", "localhost:9092");properties.put("key.deserializer", "org.apache.kafka.common.serialization.StringDeserializer");properties.put("value.deserializer", "org.apache.kafka.common.serialization.StringDeserializer");properties.put("group.id", "test-group");KafkaConsumer<String, String> kafkaConsumer = new KafkaConsumer<String,…
- dsidhwuwdojfdijoxjcifeowdjegjddlsj vvjeassdd.wd..ef.f.eeiweiuifdhdsf show complete solution.Guidelines are creating a cardlayout with 3 cards: login, fred and bob. import java.awt.event.*;import javax.swing.*;import java.awt.*;import javax.swing.JButton;import javax.swing.JFrame;import javax.swing.JLabel;import javax.swing.JPanel;import java.awt.BorderLayout;import java.awt.CardLayout;import java.awt.FlowLayout;import java.awt.Color;import java.awt.Container;import java.awt.event.ActionEvent;import java.awt.event.ActionListener; public class SimpleCardWindow extends JFrame implements ActionListener {public static final int WIDTH = 300;public static final int HEIGHT = 300; private CardLayout theCardsLayoutManager;private JPanel theCardsPanel;private JTextField userTextField;private JTextField passwordTextField;private JButton loginButton;private JButton bobWordButton;private JTextField bobEntryTextField;private JTextArea bobDisplayTextArea;private JButton bobReturnButton;private JPanel fredCard;private JPanel fredButtonPanel;private JButton fredRedColorButton;private JButton…import numpy as np import json img_codes = np.load("data/image_codes.npy") captions = json.load(open('data/captions_tokenized.json')) for img_i in range(len(captions)): for caption_i inrange(len(captions[img_i])): sentence = captions[img_i][caption_i] captions[img_i][caption_i] = ["#START#"] + sentence.split(' ') + ["#END#"] network = CaptionNet(n_tokens).to(DEVICE) optimizer = torch.optim.Adam(network.parameters(), lr=1e-3) batch_size = 128 n_epochs = 100 n_batches_per_epoch = 50 n_validation_batches = 5 for epoch in range(n_epochs): train_loss = 0 network.train() for _ in tqdm(range(n_batches_per_epoch)): images, captions = generate_batch(train_img_codes, train_captions, batch_size) images = images.to(DEVICE) captions = captions.to(DEVICE) loss_t = compute_loss(network, images, captions) # clear old gradients; do a backward pass to get new gradients; then train with opt # YOUR CODE HERE train_loss += loss_t.detach().cpu().numpy() train_loss /=…