In thermodynamic of the dissolution of Borax lab, the student's graph is below. Calculate AS? (R= 8.314 x 10-3 kJ/mole K) LN of Ksp vs 1/Temperature in Kelvin LN Ksp 0 0.0031 0.0032 0.0033 0.0034 0.0035 0.0036 0.0037 -2 -4 -6 y=-9104.5x + 26.39 R2 = 0.9713 Temperature in K-1 Series1 .........Linear (Series1) OA) 0.008075 kJ/mol K B) -75.69 kJ/mol K OC) -0.008075 kJ/mol K OD) -0.2194 kJ/mol K OE) 75.69 kJ/mol K OF) 0.2194 kJ/mol K

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section5.5: Enthalpy Changes For Chemical Reactions
Problem 1RC: 1. For the reaction 2 Hg(l) + O2(g) → 2 HgO(s), ∆rH° = 181.6 kJ/mol-rxn. What is the enthalpy change...
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In thermodynamic of the dissolution of Borax lab, the student's graph is below. Calculate
AS? (R= 8.314 x 10-3 kJ/mole K)
LN of Ksp vs 1/Temperature in Kelvin
LN Ksp
0
0.0031 0.0032 0.0033
0.0034
0.0035 0.0036 0.0037
-2
-4
-6
y=-9104.5x + 26.39
R2 = 0.9713
Temperature in K-1
Series1
.........Linear (Series1)
OA) 0.008075 kJ/mol K
B) -75.69 kJ/mol K
OC) -0.008075 kJ/mol K
OD) -0.2194 kJ/mol K
OE) 75.69 kJ/mol K
OF) 0.2194 kJ/mol K
Transcribed Image Text:In thermodynamic of the dissolution of Borax lab, the student's graph is below. Calculate AS? (R= 8.314 x 10-3 kJ/mole K) LN of Ksp vs 1/Temperature in Kelvin LN Ksp 0 0.0031 0.0032 0.0033 0.0034 0.0035 0.0036 0.0037 -2 -4 -6 y=-9104.5x + 26.39 R2 = 0.9713 Temperature in K-1 Series1 .........Linear (Series1) OA) 0.008075 kJ/mol K B) -75.69 kJ/mol K OC) -0.008075 kJ/mol K OD) -0.2194 kJ/mol K OE) 75.69 kJ/mol K OF) 0.2194 kJ/mol K
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