In the presence of excess OH", the Zn2+ (aq) ion forms a hydroxide complex ion, Zn(OH)42. Calculate the concentration of free Zn2+ ion when 1.24x10-2 mol ZnSO4(s) is added to 1.00 L of solution in which [OH" ] is held constant (buffered at pH 12.00). For Zn(OH)42, Kf = 4.6×10¹7. [Zn2+] = M

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter15: Acid–base Equilibria
Section: Chapter Questions
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In the presence of excess OH", the Zn2+ (aq) ion forms a hydroxide complex ion, Zn(OH)42. Calculate the
concentration of free Zn2+ ion when 1.24x10-2 mol ZnSO4(s) is added to 1.00 L of solution in which [OH-] is held
constant (buffered at pH 12.00). For Zn(OH)42, Kf = 4.6×10¹7.
[Zn2+] =
M
Transcribed Image Text:In the presence of excess OH", the Zn2+ (aq) ion forms a hydroxide complex ion, Zn(OH)42. Calculate the concentration of free Zn2+ ion when 1.24x10-2 mol ZnSO4(s) is added to 1.00 L of solution in which [OH-] is held constant (buffered at pH 12.00). For Zn(OH)42, Kf = 4.6×10¹7. [Zn2+] = M
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