In Exercises 1-8, solve the system by inverting the coefficient matrix and using Theorem 1.6.2. 1. x1 + x2 = 2 5x16x2 = 9 3. x1 +3x2 + x3 = 4 2x12x2 x3 = -1 2x13x2 x3 = 3

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
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Chapter7: Polynomial Equations And Factoring
Section7.8: Factoring Polynomials Completely
Problem 51E
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In Exercises 1-8, solve the system by inverting the coefficient
matrix and using Theorem 1.6.2.
2
1. x1 + x2 =
5x1 + 6x2 = 9
3. x13x2 + x3 =
4
2x1 + 2x2
x3 =
-1
2x13x2
x3 =
3
Transcribed Image Text:In Exercises 1-8, solve the system by inverting the coefficient matrix and using Theorem 1.6.2. 2 1. x1 + x2 = 5x1 + 6x2 = 9 3. x13x2 + x3 = 4 2x1 + 2x2 x3 = -1 2x13x2 x3 = 3
THEOREM 1.6.2 If A is an invertible n x n matrix, then for each n × 1 matrix b, the
system of equations Ax = b has exactly one solution, namely, x = A¯¹b.
Transcribed Image Text:THEOREM 1.6.2 If A is an invertible n x n matrix, then for each n × 1 matrix b, the system of equations Ax = b has exactly one solution, namely, x = A¯¹b.
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