II) Show the changes in the above figure after the letter H is inserted. Node data next free = 2 first = 5 0 1 2 3 4 5 6 7 F B 1 G D M K -1 7 4 -1 6 1 3 0
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there are similar questions please come up with an original answer because the questions are slighty different, thank you.
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- Write a Python code using the given function and conditions. Do not use Numpy. Use LinkedList Manipulation. Given function: def insert(self, newElement, index) Pre-condition: The list is not empty. Post-condition: This method inserts newElement at the given index of the list. If an element with the same key as newElement value already exists in the list, then it concludes the key already exists and does not insert the key. [You must also check the validity of the index].Given a scenario where you need to efficiently insert elements at the beginning of a list, which type of linked list would be most suitable? Explain why.there are similar questions please come up with an original answer because the questions are slighty different, thank you. FREE = 2 B FIRST = 5 D SHOW CHANGES IN DATA AND NEXT MEMBERS OF THE ARRAY AND THE VALUES OF FIRST AND FREE AFTER H IS INSERTED INTO THE LINKED LIST SO THE RESULTING LIST IS IN ALPHABETICAL ORDER.
- Question 30 If N represents the number of elements in the list, then the index-based add method of the LBList class is O(N). True False Question 31 A header node does not contain actual list information. True False Question 32 Any class that implements the Comparable interface must provide a compareTo method. True False Question 33 A SortedABList list can only be kept sorted based on the "natural order" of its elements. True False Question 34 O(N) is the order of growth execution time of the add operation when using the SortedArrayCollection class, assuming a collection size of N. True False Question 35 The iterator operation is required by the Iterable interface. Group of answer choices True False Question 36 O(N) is the order of growth execution time of the remove operation when using the SortedArrayCollection class, assuming a collection size of N. True False Question 37 O(N) is the order of growth execution time of the index-based add operation when…Linked list. Complete the function that takes as a parameter the head of a linked list and prints the linked list in reverse order. If the linked list had the contents: of,the,and,on,a,an,ok. Then the correct output would be: ok,an,a,on,and,the,of. Given: struct node { char word[31]; struct node *prev, next; }; void print_reverse(struct node *head) { }Both array lists and linked lists are examples of how a list may be implemented. Discuss a scenario when a linked list might be preferable than a list stored in an array. Explain your reasoning in each situation.
- Suppose that queue is implemented as an array with the special reserved slot, Suppose that the size of the array implementing queue is 100. Also, suppose that the value of queueFront is 74 and the value of queueRear is 99. a. What are the values of queueFront and queueRear after adding an element to queue?b. What are the values of queueFront and queueRear after removing an element from queue? Also, what is the position of the removed queue element?In a doubly linked list the first class is Node which we can create a new node with a given element. Its constructor also includes previous node reference prev and next node reference next. make a node object for the new element. Check if the index >= 0.If index is 0, make new node as head; else, make a temp node and iterate to the node previous to the index.If the previous node is not null, adjust the prev and next references. Print a message when the previous node is null. implement these 3 methods: insert_at_index(), delete_at_end(), display(). use these three functions above use this to name the items 1. insert_to_empty_list()2. insert_to_end()3. insert_at_index() 4. delete_at_start() 5. delete_at_end() . 6. display() let the output be OUTPUT: The list is emptyElement is: 3Element is: 10Element is: 20Element is: 30Element is: 35Element is: 38Element is: 40Element is: 50Element is: 60 Element is: 10Element is: 20Element is: 30Element is: 35Element is: 38Element is: 40Element…True or FalseA Doubly Linked List has a Header and Trailer sentinels to facilitate a more generic approach when adding and removing the head and tail nodes.
- Develop a procedure for a linked list that removes duplicate keys at once.Direction: Continue the code below and add case 4, case 5, and case 6. Add 3 more functions aside from insert, getValue, and clear from List ADT import java.util.LinkedList; import java.util.Scanner; class SampleLL { } public static void main(String[] args) { LinkedList 11s = new LinkedList(); String msg = "Choose a function: \n [1] Insert, [2]Get Value, [3]Clear, [0] Exit"; System.out.println(msg); Scanner scan= new Scanner(System.in); int choice scan.nextInt (); while(true) { } if (choice =0) { } System.exit(0); switch(choice) { } case 1: System.out.println("Enter a word/symbol:"); break; case 2: System.out.println("Enter a number: "); break; 11s.add(scan.next()); break; case 3 11s.clear(); default: System.out.println("Invalid input!"); break; System.out.println(11s.get (scan.nextInt())); System.out.println(msg); choice scan.nextInt ();please follow instructions correctly. You are required to complete the LinkedList class. This class is used as a linked list that has many methods to perform operations on the linked list. To create a linked list, create an object of this class and use the addFirst or addLast or add(must be completed) to add nodes to this linked list. Your job is to complete the empty methods. For every method you have to complete, you are provided with a header, Do not modify those headers(method name, return type or parameters). You have to complete the body of the method. package chapter02; public class LinkedList { protected LLNode list; public LinkedList() { list = null; } public void addFirst(T info) { LLNode node = new LLNode(info); node.setLink(list); list = node; } public void addLast(T info) { LLNode curr = list; LLNode newNode = new LLNode(info); if(curr == null) { list = newNode; } else…