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- https://openstax.org/books/chemistry-atoms-first-2e/pages/g-standard-thermodynamic-properties-for-selected-substancesThe solubility of Ag,CO, in water at 25 °C is measured to be 0.035 Round your answer to 2 significant digits. ☐ Use this information to calculate Ksp for Ag2CO3.What is the concentration of SO42-ions in the solution of silver sulphate with a Kçç value of 1.1x10-5 at 25 ° C?Silver sulphate dissolves in water according to the following reaction.Ag2SO4 (k) ...........> 2 Ag+ (aq) + SO42-(aq) A 1.5 L solution of silver sulfate contains 3 g of dissolved silver sulphate. If extra solid silver sulfate is added to the solution, will it dissolve in the solution? (Ag: 108 g / mol, S: 32 g / mol, O: 16 g / mol)
- Parameters to use for the problems that follow: K = 1.38 × 10-23 J/K q= 1.6 × 10-¹9 coulombs For Silicon at room temperature(T = 300°K): EG = 1.12eV N₁ = = 1 × 10¹0 cm-3 ESi = Ksito (11.8) (8.85 × 10-¹4)F/cm = Hp = 384.62cm²/V - sec, Dp = 10cm²/sec Dn = 32cm²/sec 1230.77cm²/V – sec, flin = Tn = 2.0 × 10-¹sec, Tp = 9.0 x 10-5 sec En = 8.0 × 10-2cm, Ep = 3.0 × 10-²cm 1) A sample of silicon at room temperature and in thermal equilibrium is doped with donor atoms such that ND = 4 x 10¹5 cm-³. Determine the concentration of electrons and holes. NDThe half-life is 123 min at 15.0°C. If 138.0 mL of a 0.105 M NH₂NO₂ solution is allowed to decompose, how long must the reaction proceed to yield 50.0 mL of N₂O(g) collected over water at 15.0°C and a barometric pressure of 1.01 bar? The vapour pressure of water at 15.0°C is 1.70 x 10⁻² bar.1. The concept of gas collisions can be applied to the study of metrology. Being the highest composition in atmospheric air (78% by volume), N2 has a collision diameter of 0.369 x 10° m. At 298 K and 1 atm, calculate the single collision frequency of N2 at sea level. The collision frequency of N2 decreases at higher altitude. At 11 km from the sea level, the collision frequency is 3.16 x 10° s-1. Calculate the pressure of the gas at this altitude (T = – 220 K). Determine the mean free path for N2 at the altitude of 11 km (the altitude similar in Question 1.ii.) i. ii. i.
- Write the expression for Kc for the following reactions. Ineach case indicate whether the reaction is homogeneousor heterogeneous.(a) 3 NO1g2 ∆ N2O1g2 + NO21g2(b) CH41g2 + 2 H2S1g2 ∆ CS21g2 + 4 H21g2(c) Ni1CO241g2 ∆ Ni1s2 + 4 CO1g2(d) HF1aq2 ∆ H+1aq2 + F-1aq2(e) 2 Ag1s2 + Zn2+1aq2 ∆ 2 Ag+1aq2 + Zn1s2(f) H2O1l2 ∆ H+1aq2 + OH-1aq2(g) 2 H2O1l2 ∆ 2 H+1aq2 + 2 OH-1aq2The number of vacancies N, in a crystal can be calculated using the Arrhenius equation: N₁ = Ne Ev / KT where N is total number of atoms, Ev is the activation energy for vacancy formation, and k is the Boltzmann's constant and Tis the temperature. Boltzmann constant k = 8.62 x 10¹5 ev/K a) What are the units of 7? b) What are the units for Ev? c) Under what conditions can a crystal have no vacancies?Hospital patients are often given glucose (blood sugar) through a tube connected to a bottle suspended over their beds. Suppose that this "drip" supplies glucose at the rate of 15 mg per minute, and each minute 20% of the accumulated glucose is consumed by the body. Then the amount y(t) of glucose (in excess of the normal level) in the body after t minutes satisfies the following. y' = 15 − 0.2y (Do you see why?) y(0) = 0 (zero excess glucose at t = 0) Solve this differential equation and initial condition.
- Iodine is sparingly soluble in water but much more so in carbon tetrachloride. The equilibrium constant, also called the partition coefficient, for the distribution of I2 between these two phases I2(aq) =12(CCI4) is 83 at 20°C. (a) A student adds 0.028 L of CCI4 to 0.213 L of an aqueous solution containing 0.037 g I2. The mixture is shaken and the two phases are then allowed to separate. Calculate the fraction of I2 remaining in the aqueous phase. 4.0 (b) The student now repeats the extraction of I2 with another 0.028 L of CCI4. Calculate the fraction of I2 from the original solution that remains in the aqueous phase. 4.0 (c) Compare the result in (b) with a single extraction using 0.056 L of CCI4. Comment on the difference. After a single extraction using 0.056 L of CCI4, the fraction of I2 that remains in the aqueous phase is 40 This result is larger than the result in (b), which means that a single large extraction is not as efficient as two separate smaller extractions.For this heterogeneous system 2A(aq)+3B(g)+C(l)↽−−⇀2D(s)+3E(g) the concentrations and pressures at equilibrium are [A]=1.35×10−2 M, ?B=8.62×103 Pa, [C]=14.93 M, [D]=12.55 M, and ?E=5.86×104 torr. Calculate the thermodynamic equilibrium constant, ?. please type in words don't image upload thank you.A mixture consisting of 1.000 mol H2O(g) and 1.000 mol CO(g) is placed ina reaction vessel of volume 10.00 L at 800. K. At equilibrium, 0.665 mol CO2(g) is present as a result of the reaction CO (g) + H2O (g)⇋ CO2(g)+H2(g). What is the value of Kp at 800 K?