Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter6: Types Of Chemical Reactions And Solution Stoichiometry
Section: Chapter Questions
Problem 134CP
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I am currently watching a youtube video but i am very confused on how the person found the oxidation state(the red numbers) of the elements
Transcribed Image Text:+7 -2
-2 +1 -2 +1
+2
+4 -2
MnO4 (aq) + C₂H5OH(aq) → Mn²+ (aq) + CO₂(g)
réduction
MnO₂ → Mn²+
MnO₂ → Mn²+
4
MnO₂ → Mn²+ + 4H₂O
4
MnO₂ + 8 H+ → Mn²+ + 4H₂O
MnO₂ + 8 H+ + 5 e¯ → Mn²+ + 4H₂O
12 x (MnO₂ + 8 H+ + 5 e → Mn²+ + 4H₂O)
solution acide
oxydation
C₂H5OH → CO₂
C₂H5OH → 2 CO₂
C,H5OH + 3 H,O) 2 CO,
CH5OH +3 H,O > 2 CO, + 12 H
C,H,OH + 3 H,O > 2 CO, + 12 H* +12 e
(C₂H5OH + 3 H₂O2 CO₂ + 12 H+ + 12 e¯ ) x 5
12 MnO₂ + 96 H+ + 60 e¯ → 12 Mn²+ + 48 H₂O
5 C,H,OH + 15 H,O > 10 CO, + 60 H* + 60 e-
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And how did she find these numbers
Transcribed Image Text:+7 -2
-2 +1 -2 +1
+4 -2
MnO4 (aq) + C₂H5OH(aq) → Mn²+(aq) + CO₂(g)
+2
réduction
MnO →Mn²+
MnO₂ → Mn²+
MnO₂ → Mn²+ + 4H₂O
MnO₂ + 8 H+ → Mn²+ + 4H₂O
MnO₂ + 8 H+ +5→Mn²+ + 4H₂O
12 x (MnO₂ + 8 H+ + 5 e¯ → Mn²+ + 4H₂O)
solution acide
oxydation
C₂H5OH → CO₂
C₂H5OH → 2 CO₂
C,H,OH + 3 H,O > 2 CO,
C,H5OH + 3 H,O > 2 CO, + 12 H
C₂H5OH + 3 H₂O2 CO₂ + 12 H+ +12 e
(C₂H5OH + 3 H₂O → 2 CO₂ + 12 H+ + 12 e¯ ) x 5
12 MnO₂ +96 H+ + 60 e¯ → 12 Mn²+ + 48 H₂O
5 C,H,OH + 15 H,O > 10 CO, + 60 H* + 60 e
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