How many moles of Mg3P2(s) can be produced from the reaction of0.14 mol Mg(s) with 0.020 mol P4(s)?6 Mg(s) + P4(s) → 2 Mg3P₂(s)O 0.047 molO 0.14 molO 0.020 molO 0.42 molO 0.040 mol A solution of sodium oxalate (Na2C2O4) in acidic solution is titratedwith a solution of potassium permanganate (KMnO4) according tothe following balanced chemical equation:2KMnO4(aq) + 8H₂SO4(aq) + 5Na2C2O4(aq) → 2MnSO4(aq) +8H₂O()+10CO2(g) + 5Na2SO4(aq) + K₂SO4(aq)What volume of 0.0206 M KMnO4 is required to titrate 50.0 mlsolution of 0.0262M Na2C2O4?O 50.0 mLO 25.5 mL3.42 mLO8.54 mLO63.8 mL

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How many moles of Mg3P2(s) can be produced from the reaction of 0.14 mol Mg(s) with 0.020 mol P4(s)? 6 Mg(s) + P4(s) → 2 Mg3P₂(s) O 0.047 mol O 0.14 mol O 0.020 mol O 0.42 mol O 0.040 mol

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter3: Equation, The Mole, And Chemical Formulas

Section: Chapter Questions

Problem 3.124QE

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How many moles of Mg3P2(s) can be produced from the reaction of
0.14 mol Mg(s) with 0.020 mol P4(s)?
6 Mg(s) + P4(s) → 2 Mg3P₂(s)
O 0.047 mol
O 0.14 mol
O 0.020 mol
O 0.42 mol
O 0.040 mol

A solution of sodium oxalate (Na2C2O4) in acidic solution is titrated
with a solution of potassium permanganate (KMnO4) according to
the following balanced chemical equation:
2KMnO4(aq) + 8H₂SO4(aq) + 5Na2C2O4(aq) → 2MnSO4(aq) +
8H₂O()+10CO2(g) + 5Na2SO4(aq) + K₂SO4(aq)
What volume of 0.0206 M KMnO4 is required to titrate 50.0 ml
solution of 0.0262M Na2C2O4?
O 50.0 mL
O 25.5 mL
3.42 mL
O8.54 mL
O63.8 mL

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