Here is the complete mRNA sequence from a bacterial cell: 5' ACUAGCAGGAGACGUAAGCGAUGUGCCAGAUGCGCAGUCACACAUAACUGCAAG 3' How many tRNAs will bind to the ribosome to make the protein? 8 10. 6 4
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- For the messenger RNA sequence below, find the beginning of the amino acid coding sequence and translate the sequence using the genetic code provided below. 5' - AAUUAUGGGCAAUAUGCCGGGCcGGUUAAGCG - 3' Second Letter A UGU cys u UGC Phe UCU UU U UUC UUA UAU Tyr Ser UAC UAA UAG Leu UCA Stop UGA Stop UUG UCG Stop UGG Trp CUU CU CAU His CGU c cuc Leu ccc ССА CCG Pro CÁC CAA CAG CGC CGA CGG Arg CUA CUG Gin 1st 3rd letter Ser u letter AUU ACU AAU AAC AAA AAG Asn A AUC AUA AUG lle ACC ACA AGU AGC AGA AGG Thr Lys Arg Met ACG GUU G GUC GUA GUG GCU GAU GAC GAA Asp GGU Val GCC Ala GGC Gly GCA GGA Glu GCG GAG GGG GUsing the genetic code table provided below, identify the open reading frame in this mRNA sequence, and write out the encoded 9 amino acid long peptide sequence: 5'- CGACAUGCCUAAAAUCAUGCCAUGGAGGGGGUAACCUUUU C A G U UUU Phe UCU Ser UUC Phe UCC Ser UAC UCA Ser UAA UCG Ser UAG UUA Leu Leu G C CUU Leu CUC Leu CCC CUA Leu CUG Leu AUU lle AUC lle AUA lle AUG Met ACG ACU Thr ACC Thr ACA Thr Thr A UAU Tyr UGU Cys Tyr UGC Cys CCU Pro CAU His CGU Arg Pro CAC His Pro CAA Gln CGC Arg CGA Arg CCA CCG Pro CAG Gln CGG Arg GUU Val GCU Ala GAU GUC Val GCC Ala GAC GUA Val GCA Ala GAA GUG Val GCG Ala GAG Stop UGA Stop UGG AAU Asn AAC AAA AAG AGU Asn AGC G Lys Lys Asp Asp Glu Glu Stop A Trp Ser Ser AGA Arg AGG Arg GGU Gly GGC Gly UCAG GGA Gly GGG Gly с U C A G U C A G U C A GConsider the following coding 71 nucleotide DNA template sequence (It does not contain a translational start): 5’- GTTTCCCCTATGCTTCATCACGAGGGCACTGACATGTGTAAACGAAATTCCAACCTGAGCGGCGT GTTGAG-3’ By in vitro translating the mRNA, you determined that the translated peptide is 15 amino acids long. What is the expected peptide sequence in single letter abbreviations?
- Assume the following portion of an mRNA. Find a start signal, and write the amino acid sequence that is coded for. 5'-GCCAUGUUUCCGAGUUAUCCCAAAGAUAAAAAAGAG 3'Indicate the amino acid sequence of the protein encoded by the following mRNA molecule. Use the genetic code table and assume that the very first “AUG” the ribosome encounters will serve as the start codon and specify methionine. 5’-AAUUCAUGCCCAAAUUUGGGGCACGAAGCUUCUUAGGCUAGUCCUAAAAAA-3’Using the Genetic Code Table in Figure 1.3, what is the proper sequence of amino acids in the polypeptide chain based from the given codons of MRNA (3' AAU GCC AGU GGU 5')? * U UUU Phe UCU) UC UCA UCG UAU] UAC Tyr UAA Stop UGA Stop A UAG Stop UGG Trp G UGU U UUC) UGC Cys Ser UUA Leu UUGJ CU) CCU CAU1 CGU His CUC CAC CAA CGC CC Leu CCA Pro Arg CUA CGA A Gin CUG) CG CAG CGG G AUU) ACU) AGU AAU1 Asn AAC, Thr AAA1 U AGC }Ser č A G AUC lle ACC A AUA J ACA AGA AUG Met ACG, AAG}Lys AGG Arg GGU GUU) GUC Val GCU) GCC GCA GCG J GAU1 Asp GACI Ala GGC GGA GGG ) G GUA Gly GAA1 GAG) A Glu GUG) G Figure 1.3 Alanine, Serine, Glycine, Asparagine Serine, Glycine, Asparagine, Alanine Glycine, Asparagine, Alanine, Serine Asparagine, Alanine, Serine, Glycine
- What will be the overall anti-codon sequence in tRNA for this mRNA? 5’-GUAGCCUUAUCUAGCGAUCACCGUCCGUAUUACUAGUGGCCAGACUCUUUUCACCAUGUAUAGUUG-3’The piece of eukaryotic mRNA below includes the region that codes for the binding site for the initiator tRNA needed in translation. 5'-GUUUCCCGUAUACAUGCGUGCCGGGGGC-3' Using the table below, which amino acid would you expect to be on the tRNA that is the first to bind to the A site of the ribosome? AGC AGA AGG GCA CGA CUA GGA GGC GCC CGC AUA CUC AGU CCA UCA ACA CCC UCC ACC UUC CCG UCG ACG UUU CCU UCU GCG CGG GAC AAC UGC GAA CAA GGG CAC AUC CUG AAA GCU CGU GAU AAU UGU GAG CAG GGU CAU AUU CUU AAG AUG Ala Arg Asp Asn Cys Glu Gin Gly His lle Leu Lys Met Phe Pro Ser O methionine O arginine O cysteine Ovaline UUA UUG OOOO GUA GUC UAC GUG ACU UGG UAU GUU Thr Trp Tyr Val UAA UAG UGA stopConsider the following mature mRNA from a human cell: 5' UAAUGUCGCAAUAACC 3¹ What is the sequence of amino acids in the translated protein? Second letter A First letter С U d A G บบบ UUC P U UUA UUG Leu CUU CUC CUA CUG GUU GUC GUA GUG -Phe Met-Ser-Gln Met-Arg-Lys-Ser Leu Stop-Cys-Arg-Asn-Asn C AUU AUC lle AUA ACA AUG Met ACG Val UCU UCC UCA UCG CCU CCC CCA CCG ACU ACC GCU GCC GCA GCGJ Ser Pro Thr Ala UAU UAC Tyr UGU UGC. UAA Stop UGA Stop UAG Stop UGG Trp CAC CAGGin CAU His Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. AAU Asn AAA Lys AAG. There is no start codon, resulting in no translated protein. GAU ASP GAC Glu GAA GAG G CGU CGC CGA CGG Cys AGU AGC AGA AGG Arg GGU GGC GGA GGGJ Arg ser Gly MCAG U UCAG с А SCAG U SCAG U Third letter
- Referring to the genetic code presented in Figure , give the aminoacids specified by the following bacterial mRNA sequences. Q. 5′ –GUACUAAGGAGGUUGUAUGGGUUAGGGG ACAUCAUUUUGA–3′Referring to the genetic code presented in Figure , give the aminoacids specified by the following bacterial mRNA sequences. Q. 5′ –UUUGGAUUGAGUGAAACGAUGGAUGAAAG AUUUCUCGCUUGA–3′Refer to the information on the genetic code. Use this information to determine how many amino acids are coded for by the mRNA sequence AUGCGCAGUCGGUAG. The genetic code Second letter of codon UAU UAC JUU Phenylalanine uCU UUC Phe) UUA Leucine (Leu) UUG Tyrosine (Tyr) GCysteine (Cys) UGC 1oStop codon |UGG Tryptophan (Trp) CGU CGC UcC Serine (Ser) UCA ucc CCU cC Proline (Pro) Stop codon UAG Stop codon CAU Histidine His) CU CUC CUA CUG Arginine (Arg) Leucine (Leu) cca CAA CCA CGA Glutamine (Gin) CAG AUU AUC AUA ACU Isoleucine (le) AAU AAC AGU AGC Asparagine (Asn) Serine (Ser) ACC Threonine (Thr) ACA Methicnine ACC start codon GCU Lysine (Lys) AGA Arginine (Arg) ARC AGS GAU Aspartic acid (Asp)G0 GAC GUU GUC Valine (Val) GCC Alanine (Ab) GG Glycine (Gly GUA GUG GCA GCG GA Glutamic acid (Glu) GA GGG GAG 4 15 First letter of codon Third letter of codon