Hemophilia A is caused by a recessive X-linked allele that encodes a defective form of a clotting protein. If a affected father and a mother who is known to not be a carrier have children, what percentage of female offspring will have hemophilia?
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Hemophilia A is caused by a recessive X-linked allele that encodes a defective form of a clotting protein. If a affected father and a mother who is known to not be a carrier have children, what percentage of female offspring will have hemophilia?
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- Hemophilia A is transmitted by an X-linked recessive gene.With an affected father, what is the probability that a childwill have the disease? With an affected father and a carriermother, what is the probability?O. 2 Hemophilia A is an X-linked trait where blood clotting is affected due to a mutation in a clotting factor protein. Georgio has hemophilia and attends a support group where he meets Gbenga, who does not have the disease, but whose father has hemophilia. Her mother is not affected. A) If they marry, what percentage % of all their children will have hemophilia? % B) Georgio meets another woman, Maria, at the hemophilia support group. Maria also lacks the trait, but her mother has hemophilia while her father is unaffected. # 3 Would a Georgio-Maria mating provide a larger chance of having afflicted children compared to a Georgio-Gbenga mating? C) Show how you came up with your answer to B. Edit View Insert Format Tools Table 12pt ✓ 80 F3 V Paragraph ✓ $ 4 Yes or No 000 000 F4 DO LO % 5 BIUAV T² | F5 ^ MacBook Air 6 2 F6 V & 7 F7 * 8 DII F8 ( 9 DD F9 1 0 S FHemophilia is determined by genes on the X chromosome in humans. Assume that a phenotypically normal woman whose father had hemophilia is married to a normal man. 1) What is the probability that their first son will have hemophilia? 2) What is the probability that their first daughter will have hemophilia?
- A form of hemophilia is caused by a sex-linked (X-linked) recessive gene. A phenotypically normal woman whose father had hemophilia marries a man who suffers with hemophilia. What is the probability that their first daughter will have hemophilia?Mutations in the genes for clotting factor VIII and IX cause hemophilia A and B, respectively. A woman may be heterozygous for mutations in both genes, with a mutated factor VIII allele on one X chromosome, and a mutated factor IX allele on the other. All of her sons should have either hemophilia A or B. However, on rare occasions, one of these women gives birth to a son who does not have hemophilia, and his one X chromosome does not have either mutated allele. Explain.A mother is heterozygous for the X-linked gene for colorblindness and also heterozygous for the autosomal inherited sickle cell anemia. She is married to a man who can see color normally and who is heterozygous for sickle cell trait. Using b (colorblind), B (normal color), S (normal hemoglobin), s (sickle cell), answer the following: a. What are the genotypes of the parents? b: What is the probability of having a child who is both color blind and has sickle cell anemia?
- Two forms of hemophilia are determined by genes on the X chromosome in humans. Assume that a phenotypically normal woman whose father had hemophilia is married to a normal man. What is their probability to have a son with hemophilia? (out of all children - not just the sons)Julie (a female) has hemophilia. Based on this information, what can we say about the genotypes of her parents? If Julie has children with a normal male, what is the chance that her sons have hemophilia? What is the chance that her daughters have hemophilia? A condition called Alport syndrome is caused by a dominant X linked allele. Males who have this condition usually have kidney failure, while females who are heterozygous for the condition have blood in the urine, but usually do not have kidney failure. A male has this condition and has children with an unaffected female What percent of his daughters will show any of the symptoms? What percent of his sons will show any of the symptoms?Hemophilia A, a condition in which blood does not clot properly, is a recessive trait located on the X chromosome (Xh). A woman heterozygous for the trait marries a normal male. What is the probability that this couple will have hemophiliac daughters? What is the probability that this couple will have hemophiliac sons?
- A couple are both phenotypically normal but their son suffers from hemophilla, a sex linked recessive disorder. What fraction of their children are likely to suffer from hemophilia. what fraction are likely to be carriers.Haemophilia A is a severe coagulation disorder that shows X-linked recessive inheritance. Red-green colour blindness also shows X- linked recessive inheritance. A man with both haemophilia A and colour blindness is referred for genetic counselling. Assume that his partner is not a carrier of either of these conditions. Which of the following is correct? OA. The probability that each of his daughters will be a carrier of haemophilia A is 1 in 2. OB. The probability that each of his sons will be affected with haemophilia A is 1 in 2. OC. he probability that each of his daughters will be a carrier of haemophilia A and colour blindness is 1 in 2. D. The probability that each of his sons will be affected with both haemophilia A and colour blindness is 1 in 2. OE. The probability that each of his daughters will be a carrier of both haemophilia A and colour blindness conditions is 1.Sickle cell anemia is caused by an individual carrying two recessive copies of the hemoglobin gene (hemoglobin gene is labeled Hb, and the recessive version is Hbs). Thus, to have sickle cell anemia, a person must have the genotype HbSHbS. A person that is HbAHbA carries two copies of the normal hemoglobin gene and does not have sickle cell anemia. A person that is heterozygous (HbAHbS) produces enough normal hemoglobin to not have sickle cell anemia but is also resistant to malaria. People that are heterozygous are called “carriers” because they carry the recessive allele but do not express the recessive phenotype. a. A couple are both resistant to malaria but do not have sickle cell anemia. Draw a Punnett square to represent this cross. b. What is the probability that the couple has three children where one child does not have a recessive allele, one child is resistant to malaria and does not have sickle cell anemia, and one child has sickle cell anemia?